As per the given question, the following can be calculated:
\(\frac{I_g}{I} = \frac{S}{S+G}\)
⇒ \(\frac{1}{34} = \frac{S}{S+G}\)
⇒ \(S\) = \(\frac{G}{33} = \frac{3663}{33} = 111 \ \omega\)
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