A moving coil galvanometer (resistance 100 ohms) plays the role of ammeter via using resistance 0.1 ohms. If maximum deflection current is 100 mu-A, show minimum current in the circuit so that ammeter offers maximum deflection.

As per the given data, the following can be known:

  • Resistance of galvanometer, Rg = 100 Ω
  • Maximum deflection of the given current in galvanometer, Ig = 100 μA (Symbol: mu-A)
  • Shunt resistance which is parallelly joined, S = 0.1 Ω

In the circuit, the minimum current (I) can be used to determine so that the ammeter shows maximum deflection. Shunt resistance has been attached parallelly to the galvanometer resistance in order to convert a galvanometer to an ammeter.

Simply, both of them have equal potential differences because they are parallelly connected, and the majority of the current passes through shunt resistance. IgRg represents the potential difference across the galvanometer.

Potential difference across shunt resistance = (I − Ig)S.

As they are connected in parallel, IgRg  = (I−Ig)S

Replacing the values we get,

⇒ 100 × 10−6 × 100 = (I − 100 × 10−6) × 0.1

⇒ 0.01 = (I − 100 × 10−6) × 0.1

Now, after dividing both sides by 0.1

⇒ 0.01 = (I − 100 × 10−6) × 0.1

⇒ I = 0.1 + 10−4

⇒ I = 0.1001 A

Therefore, the minimum current required in the circuit for maximum ammeter deflection is, 

\(\therefore\) I = 100.1 mA


Related Questions

  1. In A Graph Between Current I And Voltage V, Find The Portion Corresponding To Negative Resistance.
  2. 1.0 M Rectangular Loop With A Sliding Connector Is In Uniform Magnetic Field 2t Perpendicular To Plane Of Loop. Resistance Is 2 Ohms. Two Resistances, 6 Ohms And 3 Ohms, Are Connected.
  3. A Closed Coil Has 500 Turns Across Rectangular Frame Of Area 4.0 Cm2 With Resistance Of 500 Ohms. The Coil Is Plane Perpendicular To A Uniform Magnetic Field Of 0.2wb/M2. Find Amount Of Charge Through Coil If Turned Over (180 Degrees Rotation).
  4. If R, C And L Are Fundamental Quantities In A Circuit Like Resistance, Capacitance And Inductance In W, Then Find Dimensional Formula For Resistance And Capacitance.
  5. Resistance In Meter Bridge’s Two Arms Are 5 Ohms And R Ohms. When Resistance R Is Shunted With Equal Resistance, New Balance Point Becomes 1.6l1. Calculate R.
  6. Two Identical Resistors With Resistances 15 Ohm Are Connected In Series And Parallel To A Battery Of 6 V. Calculate Ratio Of Power Consumed.
  7. For The Resistor Combination, Find The Equivalent Resistance Between M and N.
  8. A Circuit Consists Of A Battery Of 3 Cells (2 V Each), A Combination Of Three Resistors, 10 Ohm, 20 Ohm And 30 Ohm, Attached Parallelly, With Plug Key And Ammeter (In Series).
  9. Two Concentric Coplanar Circular Loops Of Wire (Resistance Per Unit Length 10 4 Ohms M-1) Have Diameters 0.2 M And 2 M. With Time-Varying Potential Difference Of (4+2.5t) Applied To Larger Loop, Find Current In Smaller One.
  10. Three Incandescent Bulbs (Each 100 W) Are Attached In Series. In Another Circuit, Three More Bulbs Of Same Wattage Are Attached Parallelly To An Equal Source.

Read Also:

CBSE CLASS XII Related Questions

  • 1.
    A charged particle $+q$ in an electric field $\vec{E}$ experiences a force in the direction of the electric field. As a result, its kinetic energy changes. Similarly, the charged particle also experiences a force when it moves in a magnetic field $\vec{B}$. But this magnetic force is perpendicular to both velocity $\vec{v}$ of the charged particle and the magnetic field $\vec{B}$, so it cannot change the kinetic energy of the charged particle. Consider two charged particles 1 and 2 of masses $m$ and $\frac{m}{2}$ having charges $-q$ and $+2q$ respectively. They are accelerated from rest through the same potential difference $V$ and acquire kinetic energy $K_1$ and $K_2$. Then they enter in a region of uniform magnetic field $\vec{B}$ perpendicular to their velocities.


      • 2.
        Two air-filled capacitors of capacitances $C_1$ and $C_2$ are connected in parallel with a dc battery. After the capacitors are fully charged, a slab of dielectric constant K is inserted between the plates of each capacitor. How will the (i) charge on each capacitor and (ii) energy stored in the capacitor affected after the slab is introduced.


          • 3.
            Write two advantages of reflecting telescope over refracting telescope.


              • 4.
                Two metal spheres of radii $r_1$ and $r_2$ ($> r_1$) having charges $q_1$ and $q_2$ respectively kept in air, are brought in contact. Which of the following statements is not correct ?

                  • The total charge of the two spheres is conserved.
                  • Both spheres attain the same potential.
                  • The final potential of the system equals $\frac{1}{4\pi\epsilon_0} \frac{(q_1 + q_2)}{(r_1 + r_2)}$
                  • The final potential of the system equals $\frac{1}{4\pi\epsilon_0} \frac{(q_1 + q_2) (r_1 + r_2)}{r_1 r_2}$

                • 5.
                  A student sets up the circuit as shown in the figure to find the value of unknown resistance X and records a set of readings of the voltmeter and the ammeter by using the rheostat.


                    • 6.
                      This ‘average velocity’ is found be few mm/s for currents in range of a few amperes. How then is current established almost the instant a circuit is closed ?

                        CBSE CLASS XII Previous Year Papers

                        Comments


                        No Comments To Show