The expression for a wire’s resistance can be illustrated as:
| R = ρ l/A |

Here,
- ρ = Resistivity of a material
- l = Length of wire
- A = Cross-sectional area
Since length of the wire is doubled, then the cross-sectional area becomes half of its last value because volume of the given wire remains constant.
Now, the new cross-sectional area will become:
| A′ = A/2 |
Now, the new resistance of the wire is given as: R′ = ρl′/A′
Now, after replacing the values in the formula, we can obtain:
⇒ R′ = 4ρ l/A
With further division of new resistance with last resistance, we get:
⇒ R′/R = 4
⇒ R′ = 4R
⇒ R = 10
Hence, R’ = 40Ω
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