When a 12V battery is connected across an unknown resistor, there is a current of 2.5 mA in the circuit, determine resistance.

A current of 2.5 mA passes in the circuit because a 12 V battery has been connected with an unknown resistance.

V = 12 V

I = 2.5 mA = 2.5 × 10−3 A

Formula Used

Considering R as resistance.

If every physical condition remain constant, Ohm's law claims that the voltage across a conductor will be directly proportional to the current flowing through it. The resistance (R) of a resistor is expressed by Ohm's law.

V = IR

Calculation of Resistance

Now, by inserting the value of V and I in Ohm's law, we can obtain,

12 = 2.5 × 10−3 R

⇒ R = 4.8 × 103 Ω

Thus, the resistor's resistance is 4.8 × 103 Ω.


Related Questions

  1. What is the necessary condition for a conductor to obey Ohm's Law?
  2. Why is the curve representing Ohm's law linear?
  3. What Is Effective Resistance?
  4. A 4-ohm resistance wire is doubled on it, calculate the new resistance of the wire.
  5. How Do You Find The Resistance Of A Wire?
  6. How do you find the resistance in Ohm's law?
  7. What are the 3 forms of Ohm's law
  8. What Is Ohm's Law Graph?
  9. Why is the series arrangement not used for domestic circuits?
  10. How many 176 Ω resistors (in parallel) are required to carry 5 A on a 220 V line?
  11. What are the applications of ohm's law used in daily life?
  12. What are the limitations of Ohm's Law?
  13. Is resistance constant in Ohm's law?
  14. Does Current Increase With Voltage?
  15. Draw a circuit diagram to verify ohm’s law.
  16. The resistance R= V/I, where V=100 ± 5.0V and I = 10 ± 0.2A. What is the total error in R?

Also Read:

CBSE CLASS XII Related Questions

  • 1.
    Two parallel plate capacitors X and Y are connected in series to a 6 V battery. They have the same plate area and same plate separation but capacitor X has air between its plates, whereas capacitor Y contains a material of dielectric constant 4. Calculate the capacitances of X and Y, if the equivalent capacitance of the combination of X and Y is \( 4 \, \mu\text{F} \). Calculate the potential difference across the plates of X and Y.


      • 2.
        Four independent waves are expressed as \[ (i)\; y_1=A_1\sin\omega t, \] \[ (ii)\; y_2=A_2\sin 2\omega t, \] \[ (iii)\; y_3=A_3\cos\omega t, \] \[ (iv)\; y_4=A_4\sin\left(\omega t+\frac{\pi}{3}\right) \] The interference between two of these waves is possible in

          • (i) and (iii) only
          • (iii) and (iv) only
          • (i), (iii) and (iv) only
          • All of them

        • 3.
          Draw the number of scattered particles versus the scattering angle graph for scattering of alpha particles by a thin foil. Write two important conclusions that can be drawn from this plot.


            • 4.
              Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.


                • 5.
                  Write any two features of nuclear forces.


                    • 6.
                      If both the number of protons and the neutrons are conserved in each nuclear reaction, in what way is mass converted into energy (or vice versa) in a nuclear reaction? Explain.

                        CBSE CLASS XII Previous Year Papers

                        Comments


                        No Comments To Show