When a 12V battery is connected across an unknown resistor, there is a current of 2.5 mA in the circuit, determine resistance.

A current of 2.5 mA passes in the circuit because a 12 V battery has been connected with an unknown resistance.

V = 12 V

I = 2.5 mA = 2.5 × 10−3 A

Formula Used

Considering R as resistance.

If every physical condition remain constant, Ohm's law claims that the voltage across a conductor will be directly proportional to the current flowing through it. The resistance (R) of a resistor is expressed by Ohm's law.

V = IR

Calculation of Resistance

Now, by inserting the value of V and I in Ohm's law, we can obtain,

12 = 2.5 × 10−3 R

⇒ R = 4.8 × 103 Ω

Thus, the resistor's resistance is 4.8 × 103 Ω.


Related Questions

  1. What is the necessary condition for a conductor to obey Ohm's Law?
  2. Why is the curve representing Ohm's law linear?
  3. What Is Effective Resistance?
  4. A 4-ohm resistance wire is doubled on it, calculate the new resistance of the wire.
  5. How Do You Find The Resistance Of A Wire?
  6. How do you find the resistance in Ohm's law?
  7. What are the 3 forms of Ohm's law
  8. What Is Ohm's Law Graph?
  9. Why is the series arrangement not used for domestic circuits?
  10. How many 176 Ω resistors (in parallel) are required to carry 5 A on a 220 V line?
  11. What are the applications of ohm's law used in daily life?
  12. What are the limitations of Ohm's Law?
  13. Is resistance constant in Ohm's law?
  14. Does Current Increase With Voltage?
  15. Draw a circuit diagram to verify ohm’s law.
  16. The resistance R= V/I, where V=100 ± 5.0V and I = 10 ± 0.2A. What is the total error in R?

Also Read:

CBSE CLASS XII Related Questions

  • 1.

    A magnet held vertically, with its north pole down, is dropped along the axis of a closed solenoid placed vertically on a table. If the observer looks down from the top,

      • the induced current will flow in the anticlockwise direction.
      • the induced current will flow in the clockwise direction.
      • no induced current will flow in the solenoid.
      • the magnet will fall with a constant velocity.

    • 2.

      A ray of light MN is incident normally on the face corresponding with side AB of a prism with an isosceles right-angled triangular base ABC. Trace the path of the ray as it passes through the prism when the refractive index of the prism material is (i) $\sqrt{2}$, and (ii) $\sqrt{3}$.


        • 3.

          The number of free electrons per unit volume ($\text{m}^3$) in a wire made of copper (resistivity $1.72 \times 10^{-8}\,\Omega\,\text{m}$) is $8.5 \times 10^{28}$. Calculate the average number of collisions made by an electron in one second when an electric field is maintained in the wire.


            • 4.

              Find the ratio $\dfrac{\lambda_\alpha}{\lambda_p}$ of the de Broglie wavelength $\lambda_\alpha$ associated with an alpha particle to the de Broglie wavelength $\lambda_p$ associated with a proton if both are moving with the same velocity.


                • 5.

                  An electron is revolving around a proton in a circular orbit of radius $r$. Using classical physics, prove that the ratio of value of the angular momentum and the value of magnetic moment of electron revolving in the orbit is a constant.


                    • 6.

                      A rectangular loop of size 5 cm $\times$ 8 cm is lying in the $x$-$y$ plane in a uniform magnetic field $\vec{B} = (2.0\ \text{T})\hat{k}$. The total magnetic flux linked with the loop is:

                        • 80 Wb
                        • 16 Wb
                        • \(8 \times 10^{-2}\) Wb
                        • \(8 \times 10^{-3}\) Wb
                      CBSE CLASS XII Previous Year Papers

                      Comments


                      No Comments To Show