The resistance R=V/I, where V = 100 ± 5.0 V and I = 10 ± 0.2A. What is the total error in R?

Step 1: Given Data

Voltage = 100 ± 5.0V

Current = 10 ± 0.2A

Step 2: Formula Used

 \({\triangle R \over R} = \pm ({\triangle V \over V} + {\triangle I \over I})\)

Step 3: Calculating the error in the resistance
 \({\triangle R \over R} = \pm ({\triangle 5 \over 100} + {\triangle 0.2 \over 10})\)
 \({\triangle R \over R} = \pm (0.05 +0.02)\)
 \({\triangle R \over R} = \pm 0.07\)
The percentage error will be

 \({\triangle R \over R} \times 100 = 0.07 \times 100 \)
 \({\triangle R \over R} \times 100 = 7\)%

The total percentage error in the resistance will be 7%.


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CBSE CLASS XII Related Questions

  • 1.
    Two air-filled capacitors of capacitances $C_1$ and $C_2$ are connected in parallel with a dc battery. After the capacitors are fully charged, a slab of dielectric constant K is inserted between the plates of each capacitor. How will the (i) charge on each capacitor and (ii) energy stored in the capacitor affected after the slab is introduced.


      • 2.
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          • 3.
            Read the following paragraph and answer the questions that follow.
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              • 4.
                This ‘average velocity’ is found be few mm/s for currents in range of a few amperes. How then is current established almost the instant a circuit is closed ?


                  • 5.
                    Two metal spheres of radii $r_1$ and $r_2$ ($> r_1$) having charges $q_1$ and $q_2$ respectively kept in air, are brought in contact. Which of the following statements is not correct ?

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                    • 6.
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                        CBSE CLASS XII Previous Year Papers

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