Why Do We Use Ohm's Law?

Ohm’s law is an important law in electric circuits which represents the relationship between voltage, current, and resistance.

  • Ohm’s law can be used to control the amount of current that flows through a circuit by adding resistors in order to reduce the current flow or by removing the resistors to increase the flow of current.
  • Ohm’s law is useful in the analysis of the circuits, especially when it was combined with Kirchhoff’s Laws.

Related Questions

  1. What is the necessary condition for a conductor to obey Ohm's Law?
  2. Why is the curve representing Ohm's law linear?
  3. State Ohms law. How can it be verified experimentally?
  4. How do you find the resistance to Ohm's law?
  5. What are the 3 forms of Ohm's law
  6. What Is Ohm's Law Graph?
  7. What are the limitations of Ohm's Law?
  8. What are the applications of ohm's law used in daily life?
  9. State Ohms Law. Express It Mathematically. Define Si Unit Of Resistance.
  10. Is resistance constant in Ohm's law?
  11. Draw a circuit diagram to verify ohm’s law.

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CBSE CLASS XII Related Questions

  • 1.
    Two heaters rated as \((P_1,V)\) and \((P_2,V)\) are connected in series across a dc source of \(V/2\) volt. The power consumed by the combination will be –

      • \((P_1+P_2)\)
      • \(\dfrac{P_1+P_2}{2}\)
      • \(\dfrac{P_1P_2}{2(P_1+P_2)}\)
      • \(\dfrac{P_1P_2}{4(P_1+P_2)}\)

    • 2.
      A light copper ring is freely suspended by a light string. A bar magnet is held horizontally with its length along the axis of the ring. The magnet is moved towards the ring with its N pole facing the loop. What will happen to the ring and its position? Explain.


        • 3.
          If Bohr’s quantization postulate (angular momentum \( = \frac{nh}{2\pi} \)) is a basic law of nature, it should be equally valid for the case of planetary motion also. Why, then, do we never speak of quantization of orbits of planets around the Sun? Explain.


            • 4.
              Four independent waves are expressed as \[ (i)\; y_1=A_1\sin\omega t, \] \[ (ii)\; y_2=A_2\sin 2\omega t, \] \[ (iii)\; y_3=A_3\cos\omega t, \] \[ (iv)\; y_4=A_4\sin\left(\omega t+\frac{\pi}{3}\right) \] The interference between two of these waves is possible in

                • (i) and (iii) only
                • (iii) and (iv) only
                • (i), (iii) and (iv) only
                • All of them

              • 5.
                Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.


                  • 6.
                    Assertion (A) : The mass of a nucleus is less than the sum of the masses of the constituent nucleons. Reason (R) : Energy is absorbed when the nucleons are bound together to form a nucleus.

                      • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
                      • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
                      • Assertion (A) is true, but Reason (R) is false.
                      • Both Assertion (A) and Reason (R) are false.
                    CBSE CLASS XII Previous Year Papers

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