How Does The Resistance Of Wire Depends On Its Radius?

The resistance of a wire is inversely proportional to the cross-sectional area of a wire whereas, the cross-sectional area of a wire is directly proportional to the square of the radius of the wire.

Therefore, the resistance and the radius of the wire are inversely proportional to each other.

Therefore, as the radius increases, the resistance of the wire decreases. Therefore, the resistance of a wire depends on its radius.

Read More: Ohm’s law


Related Questions

  1. What is the necessary condition for a conductor to obey Ohm's Law?
  2. How Do You Find The Resistance Of A Wire?
  3. Why is the curve representing Ohm's law linear?
  4. State Ohms law. How can it be verified experimentally?
  5. What Is The Formula Of Ammeter?
  6. How do you find the resistance to Ohm's law?
  7. What are the 3 forms of Ohm's law
  8. What Is Ohm's Law Graph?
  9. What are the limitations of Ohm's Law?
  10. What are the applications of ohm's law used in daily life?
  11. Does Current Increase With Voltage?
  12. The resistance R= V/I, where V=100 ± 5.0V and I = 10 ± 0.2A. What is the total error in R?
  13. State Ohms Law. Express It Mathematically. Define Si Unit Of Resistance.
  14. Is resistance constant in Ohm's law?
  15. Draw a circuit diagram to verify ohm’s law.

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CBSE CLASS XII Related Questions

  • 1.
    Consider the nuclear reaction \( X \to Y + Z \). Let \( M_x \), \( M_y \), and \( M_z \) be the masses of the three nuclei X, Y, and Z respectively. Then which of the following relations hold true?

      • \( (M_x - M_z)<M_y \)
      • \( (M_x - M_y)<M_z \)
      • \( M_x>(M_y + M_z) \)
      • \( M_x<(M_y + M_z) \)

    • 2.

      An electron is revolving around a proton in a circular orbit of radius $r$. Using classical physics, prove that the ratio of value of the angular momentum and the value of magnetic moment of electron revolving in the orbit is a constant.


        • 3.
          Two point charges -Q and Q are located at points (d, 0) and (0, d) respectively, in x-y plane. The electric field E at the origin will be:

            • \(\frac{1}{4\pi\epsilon_0} \frac{\sqrt{2}Q}{d^2} (\hat{i} - \hat{j})\)
            • \(\frac{1}{4\pi\epsilon_0} \frac{\sqrt{2}Q}{d^2} (-\hat{i} - \hat{j})\)
            • \(\frac{1}{4\pi\epsilon_0} \frac{Q}{d^2} (\hat{i} - \hat{j})\)
            • \(\frac{1}{4\pi\epsilon_0} \frac{Q}{d^2} (-\hat{i} - \hat{j})\)

          • 4.

            A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of $60^\circ$ in 0.2 s. The value of emf induced in the loop will be:

              • 5 V
              • 3.5 V
              • 2.5 V
              • Zero V

            • 5.
              Draw the plot of potential energy of a pair of nucleons as a function of their separation. Write two important conclusions that can be drawn from this plot.


                • 6.
                  In a region, the electric potential varies as \(V = 10 - 50x\), where \(V\) is in volts and \(x\) is in meters. The electric field in the region is

                    • \(10\ \text{N/C}\) along \(+x\)
                    • \(10\ \text{N/C}\) along \(-x\)
                    • \(50\ \text{N/C}\) along \(+x\)
                    • \(50\ \text{N/C}\) along \(-x\)
                  CBSE CLASS XII Previous Year Papers

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