How Does The Resistance Of Wire Depends On Its Radius?

The resistance of a wire is inversely proportional to the cross-sectional area of a wire whereas, the cross-sectional area of a wire is directly proportional to the square of the radius of the wire.

Therefore, the resistance and the radius of the wire are inversely proportional to each other.

Therefore, as the radius increases, the resistance of the wire decreases. Therefore, the resistance of a wire depends on its radius.

Read More: Ohm’s law


Related Questions

  1. What is the necessary condition for a conductor to obey Ohm's Law?
  2. How Do You Find The Resistance Of A Wire?
  3. Why is the curve representing Ohm's law linear?
  4. State Ohms law. How can it be verified experimentally?
  5. What Is The Formula Of Ammeter?
  6. How do you find the resistance to Ohm's law?
  7. What are the 3 forms of Ohm's law
  8. What Is Ohm's Law Graph?
  9. What are the limitations of Ohm's Law?
  10. What are the applications of ohm's law used in daily life?
  11. Does Current Increase With Voltage?
  12. The resistance R= V/I, where V=100 ± 5.0V and I = 10 ± 0.2A. What is the total error in R?
  13. State Ohms Law. Express It Mathematically. Define Si Unit Of Resistance.
  14. Is resistance constant in Ohm's law?
  15. Draw a circuit diagram to verify ohm’s law.

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CBSE CLASS XII Related Questions

  • 1.
    With the help of a labelled diagram, explain the principle, construction and working of an a.c. generator.


      • 2.
        An astronomical telescope consists of two converging lenses. One of them of large aperture and large focal length is called objective lens and the other one, of smaller focal length and smaller aperture is called the eyepiece. It is used to see distant objects which are not seen clearly with naked eyes. The image formed by the objective lens acts as an object for the eyepiece and the final image produced by the eyepiece is magnified.


          • 3.
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            In an experiment with convex lens of focal length f, the screen is fixed at a distance D from the object. A student slowly moves the lens away from the object towards the screen and finds that she is able to form sharp image of the object for two positions of the lens. The distance between these two positions of the lens is d.


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                A charged particle $+q$ in an electric field $\vec{E}$ experiences a force in the direction of the electric field. As a result, its kinetic energy changes. Similarly, the charged particle also experiences a force when it moves in a magnetic field $\vec{B}$. But this magnetic force is perpendicular to both velocity $\vec{v}$ of the charged particle and the magnetic field $\vec{B}$, so it cannot change the kinetic energy of the charged particle. Consider two charged particles 1 and 2 of masses $m$ and $\frac{m}{2}$ having charges $-q$ and $+2q$ respectively. They are accelerated from rest through the same potential difference $V$ and acquire kinetic energy $K_1$ and $K_2$. Then they enter in a region of uniform magnetic field $\vec{B}$ perpendicular to their velocities.


                  • 5.
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                      • 6.
                        Derive an expression for the capacitance of a parallel plate capacitor of plate area A and plate separation d with air present between the plates.

                          CBSE CLASS XII Previous Year Papers

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