A 1m potentiometer wire (PQ) is joined to a standard cell E1. Another cell E2 (emf 1.02 V) is joined with resistance ‘r’ and switch S. With the switch open, the null position is acquired at a distance of 49 cm from Q. Find potential gradient.

A potentiometer can be represented as a three-terminal resistor with either rotating or sliding contact that develops an adjustable voltage divider. As per the given question:

Potentiometer

  • PQ= 1 m
  • QJ = 49 cm
  • PJ = 51 cm

V/l = 1.02/51 = 0.02 v/cm


Related Questions

  1. Sensitivity of potentiometer can be increased by_______.
  2. Why Do We Prefer A Potentiometer With A Longer Bridge Wire?
  3. Why High Resistance Is Used In Potentiometer?
  4. What are the types of potentiometers?
  5. Which Metal Is Used In Potentiometer?
  6. A Potentiometer Wire AB of Length L and Resistance 12r is Connected to a Cell D With Emf \(\epsilon\) and Internal Resistance 3r. Find Length AJ Wherein The Galvanometer as Shown in Image Shows No Deflection.
  7. Why Potentiometer Is Preferred Over Voltmeter?
  8. State the Working Principle of a Potentiometer.
  9. What is a null point in a potentiometer?
  10. Copper is not used as potentiometer wire because?
  11. What is a DC Potentiometer?
  12. What are the advantages of a potentiometer?
  13. How is potential gradient measured?
  14. What is the symbol for a potentiometer?
  15. What is balance point in potentiometer?
  16. How does a potentiometer measure EMF?
  17. What Is Balancing Length In Potentiometer?

Also Check:

CBSE CLASS XII Related Questions

  • 1.
    Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:

      • attract with a force \( \frac{F}{2} \)
      • repel with a force \( \frac{F}{2} \)
      • repel with a force \( F \)
      • attract with a force \( F \)

    • 2.
      A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of 60° in 0.2 s. The value of emf induced in the loop will be:

        • 5 V
        • 3.5 V
        • 2.5 V
        • Zero V

      • 3.
        If Bohr’s quantization postulate (angular momentum \( = \frac{nh}{2\pi} \)) is a basic law of nature, it should be equally valid for the case of planetary motion also. Why, then, do we never speak of quantization of orbits of planets around the Sun? Explain.


          • 4.
            Assertion (A) : All atoms have a net magnetic moment. Reason (R) : A current loop does not always behave as a magnetic dipole.

              • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
              • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
              • Assertion (A) is true, but Reason (R) is false.
              • Both Assertion (A) and Reason (R) are false.

            • 5.
              If both the number of protons and the neutrons are conserved in each nuclear reaction, in what way is mass converted into energy (or vice versa) in a nuclear reaction? Explain.


                • 6.
                  Four independent waves are expressed as \[ (i)\; y_1=A_1\sin\omega t, \] \[ (ii)\; y_2=A_2\sin 2\omega t, \] \[ (iii)\; y_3=A_3\cos\omega t, \] \[ (iv)\; y_4=A_4\sin\left(\omega t+\frac{\pi}{3}\right) \] The interference between two of these waves is possible in

                    • (i) and (iii) only
                    • (iii) and (iv) only
                    • (i), (iii) and (iv) only
                    • All of them
                  CBSE CLASS XII Previous Year Papers

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