A potentiometer can be defined as a three-terminal resistor with either rotating or sliding contact that develops an adjustable voltage divider. Now, as per the given question, we following can be said:
- Potentiometer wire (L) = 4m
- Resistance (R) = 10Ω
- EMF of the cell = 3V
The potential across potentiometer wire can be estimated as:
Vp = 10 × I
Here, I = E/R
Thus, after replacing the values:
⇒ I = 3/10
⇒ I = 0.3 A
⇒ Vp = 10 × 0.3
⇒ Vp = 3V
Potential gradient can be expressed as the potential difference per unit length. The SI unit of the potential gradient can be defined by replacing the unit of potential difference or voltage and length.
Therefore, it can be represented as:
Potential gradient (k) = Vp/L
⇒ k = 3/4
⇒ Hence, k = 0.75 Vm-1
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