State and explain Joule's Law of Heating?

Joule’s law is an expression of the rate at which the resistance of a circuit changes electric energy into heat energy. The heat produced due to the flow of this current in an electric wire is represented in Joules.

Joule’s law of heating denotes the connection between heat generated via a conductor by flowing electric current.

Q = I2 x R x T

  • Where Q is the amount of heat
  • I is the electric current
  • R is the amount of electric resistance in the conductor
  • T denotes time

As we know that

V = W/Q ----- (1)

Where

From equation 1, we get

W = VQ ----- (2)

Current (I) = Q/T ----- (3)

And

Q = IT ----- (4)

Substituting equation (4) in equation (3) we get

W = VIT ----- (5)

Considering Ohm’s law

V = IR ----- (6)

Now, substituting equation (6) in equation (5) we get

W = IRIT

W = I2RT


Related Questions

  1. What is the necessary condition for a conductor to obey Ohm's Law?
  2. What Is Ohm's Law Graph?
  3. Why is the curve representing Ohm's law linear?
  4. State Ohms law. How can it be verified experimentally?
  5. Why Do We Use Ohm's Law?
  6. How do you find the resistance to Ohm's law?
  7. What Is Effective Resistance?
  8. State Ohms Law. Express It Mathematically. Define Si Unit Of Resistance.
  9. What are the limitations of Ohm's Law?
  10. What are the 3 forms of Ohm's law
  11. Draw a circuit diagram to verify ohm’s law.
  12. What Is The Basic Principle Of Ohm's Law?
  13. Is resistance constant in Ohm's law?
  14. What are the applications of ohm's law used in daily life?
  15. Obtain the equation J = σE of Ohm's law on the basis of drift velocity

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CBSE CLASS XII Related Questions

  • 1.
    An astronomical telescope consists of two converging lenses. One of them of large aperture and large focal length is called objective lens and the other one, of smaller focal length and smaller aperture is called the eyepiece. It is used to see distant objects which are not seen clearly with naked eyes. The image formed by the objective lens acts as an object for the eyepiece and the final image produced by the eyepiece is magnified.


      • 2.
        Derive an expression for the capacitance of a parallel plate capacitor of plate area A and plate separation d with air present between the plates.


          • 3.
            A student sets up the circuit as shown in the figure to find the value of unknown resistance X and records a set of readings of the voltmeter and the ammeter by using the rheostat.


              • 4.
                With the help of a labelled diagram, explain the principle, construction and working of an a.c. generator.


                  • 5.
                    Two metal spheres of radii $r_1$ and $r_2$ ($> r_1$) having charges $q_1$ and $q_2$ respectively kept in air, are brought in contact. Which of the following statements is not correct ?

                      • The total charge of the two spheres is conserved.
                      • Both spheres attain the same potential.
                      • The final potential of the system equals $\frac{1}{4\pi\epsilon_0} \frac{(q_1 + q_2)}{(r_1 + r_2)}$
                      • The final potential of the system equals $\frac{1}{4\pi\epsilon_0} \frac{(q_1 + q_2) (r_1 + r_2)}{r_1 r_2}$

                    • 6.
                      Consider a cylindrical conductor of length \( l \) and area of cross-section \( A \). Current \( I \) is maintained in the conductor and electrons drift with velocity \( \vec{v}_d \, (|\vec{v}_d| = \frac{eE}{m} \tau) \), where symbols have their usual meanings. Show that the conductivity of the material of the conductor is given by \[ \sigma = \frac{n e^2 \tau}{m}. \]

                        CBSE CLASS XII Previous Year Papers

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