An electric lamp of 100 Ohms, a toaster of resistance 50 Ohms, and a water filter of resistance 500 Ohms are connected in parallel to a 220 V source. What is the resistance of an electric iron connected to the same source that takes as much current as all

Given parameters:

Resistance of electric lamp (R₁) = 100 Ω
Resistance of toaster (R₂) = 50 Ω
Resistance of water filter (R₃) = 500 Ω
A potential difference of the source (V) = 220 V

To find:

The flow of electric current through the electric iron.
Resistance of an electric iron

The three resistors are connected in parallel as shown –

All 3 resistances are connected in parallel

Solution:
1) The total resistance (R) can be calculated by –

1/R = 1/R₁ + 1/R₂ + 1/R₃

1/R = 1/100 + 1/50 + 1/500

1/R = (5 + 10 + 1)/500

1/R = 16/500

Total Resistance (R) = 500/16 = 31.25 Ω

2) According to Ohm’s law, the current through a conductor is directly proportional to the voltage across two points of a conductor.

V = IR

Where R is constant called resistance.

R = V/I

I = 220 × (16/500)

I = 7.04 A

Therefore, the resistance of the electric iron is 31.25 Ω and the current flowing through it is 7.04 A.

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An electric lamp of 100 Ohms, a toaster of resistance 50 Ohms, and a water filter of resistance 500 Ohms are connected in parallel to a 220 V source. What is the resistance of an electric iron connected to the same source that takes as much current?

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An electric lamp of 100 Ohms, a toaster of resistance 50 Ohms, and a water filter of resistance 500 Ohms are connected in parallel to a 220 V source. What is the resistance of an electric iron connected to the same source that takes as much current?

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CBSE CLASS XII Related Questions

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2. Draw the number of scattered particles versus the scattering angle graph for scattering of alpha particles by a thin foil. Write two important conclusions that can be drawn from this plot.

3.A light copper ring is freely suspended by a light string. A bar magnet is held horizontally with its length along the axis of the ring. The magnet is moved towards the ring with its N pole facing the loop. What will happen to the ring and its position? Explain.

5.Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:

6.Assertion (A) : The mass of a nucleus is less than the sum of the masses of the constituent nucleons. Reason (R) : Energy is absorbed when the nucleons are bound together to form a nucleus.

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Comments

SUBSCRIBE TO OUR NEWS LETTER

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A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of 60° in 0.2 s. The value of emf induced in the loop will be:

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