Three identical cells of 4 V and internal resistance r are connected in series?

Internal resistance can be defined as the opposition to the current’s flow supplied by the cells and batteries themselves, resulting in heat production.

Step 1: Given Data

As per the question,

Total EMF = 4 \(\times\) 3 = 12 V
Total Resistance = 6 + 3r
Current = 2 A

Step 2: Calculation of Given Data

The question can be solved using Ohm’s Law. Therefore,

2 = \({{12} \over (6+3r)}\)

⇒ 2 (6+3r) =12
⇒ 12 + 6r = 12
⇒ 6r = 12 – 12 = 0
⇒ r = \({{0} \over 6}\) = 0

Hence, the internal resistance of each cell is 0.

Read More: Ohm’s Law and its Limitations

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Three identical cells of 4 V and internal resistance r, are connected in series to a 6 resistor 2 A current in circuit. What is the internal resistance of each cell?

Step 1: Given Data

Step 2: Calculation of Given Data

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Three identical cells of 4 V and internal resistance r, are connected in series to a 6 resistor 2 A current in circuit. What is the internal resistance of each cell?

Step 1: Given Data

Step 2: Calculation of Given Data

CBSE CLASS XII Related Questions

1.Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.

2.Four independent waves are expressed as \[ (i)\; y_1=A_1\sin\omega t, \] \[ (ii)\; y_2=A_2\sin 2\omega t, \] \[ (iii)\; y_3=A_3\cos\omega t, \] \[ (iv)\; y_4=A_4\sin\left(\omega t+\frac{\pi}{3}\right) \] The interference between two of these waves is possible in

3.Two heaters rated as \((P_1,V)\) and \((P_2,V)\) are connected in series across a dc source of \(V/2\) volt. The power consumed by the combination will be –

4. Write any two features of nuclear forces.

5.Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:

6.Assertion (A) : The mass of a nucleus is less than the sum of the masses of the constituent nucleons. Reason (R) : Energy is absorbed when the nucleons are bound together to form a nucleus.

Similar Physics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.

2.
Four independent waves are expressed as \[ (i)\; y_1=A_1\sin\omega t, \] \[ (ii)\; y_2=A_2\sin 2\omega t, \] \[ (iii)\; y_3=A_3\cos\omega t, \] \[ (iv)\; y_4=A_4\sin\left(\omega t+\frac{\pi}{3}\right) \] The interference between two of these waves is possible in

3.
Two heaters rated as \((P_1,V)\) and \((P_2,V)\) are connected in series across a dc source of \(V/2\) volt. The power consumed by the combination will be –

4.
Write any two features of nuclear forces.

5.
Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:

6.
Assertion (A) : The mass of a nucleus is less than the sum of the masses of the constituent nucleons. Reason (R) : Energy is absorbed when the nucleons are bound together to form a nucleus.