Three identical cells of 4 V and internal resistance r, are connected in series to a 6 resistor 2 A current in circuit. What is the internal resistance of each cell?

Internal resistance can be defined as the opposition to the current’s flow supplied by the cells and batteries themselves, resulting in heat production.

Step 1: Given Data

As per the question,

  • Total EMF = 4 \(\times\) 3 = 12 V
  • Total Resistance = 6 + 3r
  • Current = 2 A

Step 2: Calculation of Given Data

The question can be solved using Ohm’s Law. Therefore,

2 = \({{12} \over (6+3r)}\)

⇒ 2 (6+3r) =12
⇒ 12 + 6r = 12
⇒ 6r = 12 – 12 = 0
⇒ r = \({{0} \over 6}\) = 0

Hence, the internal resistance of each cell is 0.

Read More: Ohm’s Law and its Limitations


Related Questions:

  1. What is the necessary condition for a conductor to obey Ohm's Law?
  2. What is Effective Resistance?
  3. Why is the curve representing Ohm's law linear?
  4. Why Do We Use Ohm's Law?
  5. How many 176 ohm resistors (in parallel) are required to carry 5 A on a 220 V line?
  6. State Ohms law. How can it be verified experimentally?
  7. How do you find the resistance to Ohm's law?
  8. What are the 3 forms of Ohm's law
  9. What Is Ohm's Law Graph?
  10. What are the limitations of Ohm's Law?
  11. What are the applications of ohm's law used in daily life?
  12. State Ohms Law. Express It Mathematically. Define Si Unit Of Resistance.
  13. Is resistance constant in Ohm's law?
  14. Draw a circuit diagram to verify ohm’s law.

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