Three identical cells of 4 V and internal resistance r, are connected in series to a 6 resistor 2 A current in circuit. What is the internal resistance of each cell?

Internal resistance can be defined as the opposition to the current’s flow supplied by the cells and batteries themselves, resulting in heat production.

Step 1: Given Data

As per the question,

• Total EMF = 4 \(\times\) 3 = 12 V
• Total Resistance = 6 + 3r
• Current = 2 A

Step 2: Calculation of Given Data

The question can be solved using Ohm’s Law. Therefore,

2 = \({{12} \over (6+3r)}\)

⇒ 2 (6+3r) =12
⇒ 12 + 6r = 12
⇒ 6r = 12 – 12 = 0
⇒ r = \({{0} \over 6}\) = 0

Hence, the internal resistance of each cell is 0.

Read More: Ohm’s Law and its Limitations

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