Find the current through a resistance 2 ohm if the voltage across the resistance is 6 V.

Step 1: Given: Resistance = 2\(\Omega\)

Voltage = 6 V

To find: Current, I =? 

Step 2: Calculating current

From Ohm’s law, we know that,

V = IR

I = V/R

I = 6/2

I = 3 A
 
Therefore the value of the current through the resistance is 3 A.


Related Questions

  1. Define: 1 volt, Potential difference
  2. A small bulb has a resistance of 2 ohms when it is cold. It draws 0.4-ampere current from a source of 4V and then starts glowing. Calculate the resistance when it is glowing
  3. What is the necessary condition for a conductor to obey Ohm's Law?
  4. What Is Effective Resistance?
  5. Obtain the equation J = σE of Ohm's law on the basis of drift velocity
  6. Why is the curve representing Ohm's law linear?
  7. State Ohms law. How can it be verified experimentally?
  8. State And Explain Joules Law Of Heating.
  9. Draw a circuit diagram to verify ohm’s law.
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  11. What Is The Basic Principle Of Ohm's Law?
  12. Obtain the equation of Ohm's law on the basis of drift velocity
  13. Is resistance constant in Ohm's law?
  14. What are the applications of ohm's law used in daily life?
  15. Why Do We Use Ohm's Law?

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CBSE CLASS XII Related Questions

  • 1.
    The resistance of a metal wire at \( 20^\circ \text{C} \) is \( 1.05 \, \Omega \) and at \( 100^\circ \text{C} \) is \( 1.38 \, \Omega \). Determine the temperature coefficient of resistivity of this metal.


      • 2.
        An astronomical telescope consists of two converging lenses. One of them of large aperture and large focal length is called objective lens and the other one, of smaller focal length and smaller aperture is called the eyepiece. It is used to see distant objects which are not seen clearly with naked eyes. The image formed by the objective lens acts as an object for the eyepiece and the final image produced by the eyepiece is magnified.


          • 3.
            Read the following paragraph and answer the questions that follow.
            A p-type or n-type semiconductor can be converted into a p-n junction by doping it with suitable impurity. The motion of majority charge carriers causes diffusion current across the junction while the barrier electric field causes motion of minority carriers for drift current. In case of unbiased diode, the diffusion and drift currents are equal. This equilibrium is disturbed by the biasing batteries. Diodes, therefore, allow currents in one direction. This property of diode is used in making rectifiers.


              • 4.
                A student sets up the circuit as shown in the figure to find the value of unknown resistance X and records a set of readings of the voltmeter and the ammeter by using the rheostat.


                  • 5.
                    Consider the nuclear reaction \( X \to Y + Z \). Let \( M_x \), \( M_y \), and \( M_z \) be the masses of the three nuclei X, Y, and Z respectively. Then which of the following relations hold true?

                      • \( (M_x - M_z)<M_y \)
                      • \( (M_x - M_y)<M_z \)
                      • \( M_x>(M_y + M_z) \)
                      • \( M_x<(M_y + M_z) \)

                    • 6.
                      Two air-filled capacitors of capacitances $C_1$ and $C_2$ are connected in parallel with a dc battery. After the capacitors are fully charged, a slab of dielectric constant K is inserted between the plates of each capacitor. How will the (i) charge on each capacitor and (ii) energy stored in the capacitor affected after the slab is introduced.

                        CBSE CLASS XII Previous Year Papers

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