CUET 2026 May 24 Shift 1 General Aptitude Test Question Paper is available for download here. NTA conducted the CUET 2026 exam from 11th May to 31st May.
- CUET 2026 General Aptitude Test exam consists of 50 questions for 250 marks to be attempted in 60 minutes.
- As per the marking scheme, 5 marks are awarded for each correct answer, and 1 mark is deducted for incorrect answer.
Candidates can download CUET 2026 May 24 Shift 1 General Aptitude Test Question Paper with Answer Key and Solution PDF from links provided below.
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CUET 2026 General Aptitude Test May 24 Shift 1 Question Paper with Solution PDF
| CUET May 24 Shift 1 General Aptitude Test Question Paper 2026 | Download PDF | Check Solutions |
Ankit, Ashish and Arun earned a profit of Rs. 12 lakh from a year from their business. Ankit retained Rs. 6 lakh, while Ashish and Arun each kept Rs. 3 lakh. What is the ratio of their profits from the business?
View Solution
Step 1: Understanding the Question:The total profit is Rs. 12 lakh. It is shared among three people, and the share of each person is given directly. We only need to write the three shares as a ratio and simplify it.
Step 2: Key Formula or Approach:
A ratio compares amounts of the same kind. To simplify it, divide every term by the same common factor.
\[ \text{Ratio} = \text{Ankit} : \text{Ashish} : \text{Arun} \]
Step 3: Write the shares:
Ankit kept Rs. 6 lakh. Ashish kept Rs. 3 lakh. Arun kept Rs. 3 lakh.
Check: \(6 + 3 + 3 = 12\), which matches the total profit.
So the ratio is \(6 : 3 : 3\).
Step 4: Simplify the ratio:
The highest common factor of 6, 3 and 3 is 3. Divide each term by 3.
\[ 6 : 3 : 3 = \frac{6}{3} : \frac{3}{3} : \frac{3}{3} = 2 : 1 : 1 \]
Step 5: Check option (1) 3:1:2:
This option gives Arun double the share of Ashish. But Ashish and Arun kept equal amounts. So option (1) is wrong.
Step 6: Check options (3) and (4):
Option (3) 3:1:1 makes Ankit's share 3 times Ashish's share, but it is only 2 times (6 against 3). Option (4) 4:1:2 makes Arun's share double Ashish's, but they are equal. So both are wrong.
Final Answer:
The ratio of the profits of Ankit, Ashish and Arun is 2:1:1. This is option (2). \[ \boxed{2:1:1} \]
An article is sold for Rs. 2000 with profit of 25%. What would have been the percentage of profit, if it was sold for Rs. 1800?
View Solution
Step 1: Understanding the Question:The article was sold at Rs. 2000 and this gave a profit of 25 percent. From this we can find the cost price. Then we find the profit percentage when the selling price is Rs. 1800.
Step 2: Key Formula or Approach:
Profit percent is always taken on the cost price.
\[ \text{Profit percent} = \frac{SP - CP}{CP} \times 100 \]
\[ CP = \frac{SP \times 100}{100 + \text{Profit percent}} \]
Step 3: Find the cost price:
With a profit of 25 percent, the selling price is 125 percent of the cost price.
\[ CP = \frac{2000 \times 100}{125} = 1600 \]
So the cost price is Rs. 1600.
Step 4: Find the new profit:
Now the selling price is Rs. 1800.
Profit = \(1800 - 1600 = 200\).
\[ \text{Profit percent} = \frac{200}{1600} \times 100 = 12.5 \]
So the profit is 12.5 percent.
Step 5: Check the wrong options:
10 percent would need a selling price of Rs. 1760. 11 percent would need Rs. 1776. 13.5 percent would need Rs. 1816. None of these equals Rs. 1800, so options (1), (2) and (4) are wrong.
Final Answer:
The profit would have been 12.5 percent. This is option (3). \[ \boxed{12.5 \%} \]
At what rate of compound interest per annum, a sum of Rs 1800 becomes Rs 2178 in two years?
View Solution
Step 1: Understanding the Question:A principal of Rs. 1800 grows to Rs. 2178 in two years under compound interest. We must find the yearly rate.
Step 2: Key Formula or Approach:
For compound interest with yearly compounding, the amount is
\[ A = P \left(1 + \frac{r}{100}\right)^n \]
Here \(P = 1800\), \(A = 2178\) and \(n = 2\).
Step 3: Set up the equation:
\[ 2178 = 1800 \left(1 + \frac{r}{100}\right)^2 \]
\[ \left(1 + \frac{r}{100}\right)^2 = \frac{2178}{1800} = \frac{121}{100} \]
Step 4: Solve for r:
Take the square root of both sides.
\[ 1 + \frac{r}{100} = \frac{11}{10} \]
\[ \frac{r}{100} = \frac{1}{10} \Rightarrow r = 10 \]
Step 5: Check the options:
With 10 percent, year 1 gives \(1800 \times 1.1 = 1980\), and year 2 gives \(1980 \times 1.1 = 2178\). This matches. With 11 percent the amount would be \(1800 \times 1.2321 = 2217.78\), with 12 percent it would be 2257.92 and with 13 percent it would be 2298.42. These do not match, so options (1), (2) and (3) are wrong.
Final Answer:
The rate of compound interest is 10 percent per annum. This is option (4). \[ \boxed{10 \%} \]
For a circle of radius r and \(\theta\) as central angle, which of the following statements is/are correct?
(A) Volume = 2/3 \(\pi\) r2
(B) Circumference = 2\(\pi\)r
(C) Area = \(\pi\) r2
(D) Area of sector = \(\frac{\pi r^2 \theta}{360}\)
Choose the correct answer from the options given below:
View Solution
Step 1: Understanding the Question:We must check four statements about a circle of radius \(r\) and a sector with central angle \(\theta\) in degrees. Then we pick the option that lists only the true ones.
Step 2: Key Formulae:
Circumference of a circle: \(2\pi r\).
Area of a circle: \(\pi r^2\).
Area of a sector with central angle \(\theta\) in degrees: \(\frac{\theta}{360} \times \pi r^2\).
Step 3: Check statement (A):
A circle is a flat figure, so it has an area but no volume. Also, \(\frac{2}{3}\pi r^2\) is not the area formula. So (A) is FALSE.
Step 4: Check statement (B):
The distance around a circle is \(2\pi r\). So (B) is TRUE.
Step 5: Check statement (C):
The area of a circle is \(\pi r^2\). So (C) is TRUE.
Step 6: Check statement (D):
A sector is the fraction \(\frac{\theta}{360}\) of the whole circle. So its area is \(\frac{\pi r^2 \theta}{360}\). So (D) is TRUE.
Step 7: Pick the option:
The true statements are (B), (C) and (D). Options (1), (3) and (4) all include (A), which is false. Only option (2) lists (B), (C) and (D).
Final Answer:
Statements (B), (C) and (D) are correct. This is option (2). \[ \boxed{\text{(B), (C) and (D) only}} \]
Match List-I with List-II
| List-I (Statements, etc.) | List-II (Values, etc.) |
|---|---|
| (A) Coordinates of origin | (I) (0, y) |
| (B) Distance of a point from itself | (II) (x, 0) |
| (C) Any point on the y axis | (III) (0, 0) |
| (D) Any point on the x axis | (IV) 0 |
View Solution
Step 1: Understanding the Question:We must match each item of List-I with its value in List-II. All items come from basic coordinate geometry.
Step 2: Match (A) Coordinates of origin:
The origin is the point where the x axis and y axis meet. Both coordinates are zero. So (A) matches (III) (0, 0).
Step 3: Match (B) Distance of a point from itself:
The distance between a point and itself is always zero. So (B) matches (IV) 0.
Step 4: Match (C) Any point on the y axis:
On the y axis, the x coordinate is zero and y can be anything. So the point looks like (0, y). So (C) matches (I).
Step 5: Match (D) Any point on the x axis:
On the x axis, the y coordinate is zero and x can be anything. So the point looks like (x, 0). So (D) matches (II).
Step 6: Compare with the options:
The matching is A-III, B-IV, C-I, D-II. Option (1) gives A-I, which is wrong. Option (2) gives A-II, which is wrong. Option (4) gives A-IV, which is wrong because the origin is a point, not a number. Only option (3) fits.
Final Answer:
The correct matching is A-III, B-IV, C-I, D-II. This is option (3). \[ \boxed{\text{A-III, B-IV, C-I, D-II}} \]
The total sum in marks for 50 students in a class is 2250. Find the average marks in the class.
View Solution
Step 1: Understanding the Question:We know the total marks of all students and the number of students. The average is the marks that each student would get if the total were shared equally.
Step 2: Key Formula or Approach:
\[ \text{Average} = \frac{\text{Sum of all marks}}{\text{Number of students}} \]
Step 3: Calculate:
Sum of marks = 2250. Number of students = 50.
\[ \text{Average} = \frac{2250}{50} = 45 \]
Step 4: Check the other options:
If the average were 40, the total would be \(40 \times 50 = 2000\). For 50 it would be 2500, and for 55 it would be 2750. Only 45 gives \(45 \times 50 = 2250\), so options (1), (3) and (4) are wrong.
Final Answer:
The average marks in the class are 45. This is option (2). \[ \boxed{45} \]
If a dice is thrown, what is the probability of getting 6 ?
View Solution
Step 1: Understanding the Question:A standard dice has six faces, numbered 1 to 6. When it is thrown, any one face can come up. We need the chance that the face showing is 6.
Step 2: Key Formula or Approach:
\[ P(E) = \frac{\text{Number of favourable outcomes}}{\text{Total number of possible outcomes}} \]
Step 3: Count the outcomes:
Total outcomes: 1, 2, 3, 4, 5, 6, so there are 6.
Favourable outcomes: only the face 6, so there is 1.
Step 4: Calculate:
\[ P(6) = \frac{1}{6} \]
Step 5: Check the other options:
Option (1) 1/3 would be the chance of getting a 5 or 6, which is 2 faces. Option (2) 2/3 would be 4 faces. Option (3) 3/4 does not fit any count out of 6. So options (1), (2) and (3) are wrong.
Final Answer:
The probability of getting 6 is 1/6. This is option (4). \[ \boxed{\frac{1}{6}} \]
In how many ways can a team of 11 cricket players be chosen from 14 players?
View Solution
Step 1: Understanding the Question:We must pick 11 players out of 14. The order of picking does not matter, only who is in the team. So this is a combination problem.
Step 2: Key Formula or Approach:
The number of ways to choose \(r\) items from \(n\) is \(\binom{n}{r} = \dfrac{n!}{r!\,(n-r)!}\). Also \(\binom{n}{r} = \binom{n}{n-r}\), which makes the sum easier.
Step 3: Detailed Explanation:
Here \(n = 14\) and \(r = 11\). Choosing 11 players to include is the same as choosing 3 players to leave out.
\[ \binom{14}{11} = \binom{14}{3} = \frac{14 \times 13 \times 12}{3 \times 2 \times 1} \]
\[ = \frac{2184}{6} = 364 \]
Step 4: Check the other options:
396, 416 and 436 do not match the value of \(\binom{14}{3}\). They can come from arithmetic slips, such as dividing 14 x 13 x 12 by a wrong number or using a permutation count. So only 364 is right.
Final Answer:
The team can be chosen in 364 ways. \[ \boxed{364} \]
If \(2x + 3y = 18\) and \(y = 2\), then the value of \(x\) is:
View Solution
Step 1: Understanding the Question:We have one equation with two unknowns and the value of \(y\) is given. So we can put \(y\) into the equation and find \(x\).
Step 2: Key Formula or Approach:
Substitute the known value, then solve the simple linear equation in \(x\) by isolating the term with \(x\).
Step 3: Detailed Explanation:
Put \(y = 2\) in \(2x + 3y = 18\).
\[ 2x + 3(2) = 18 \]
\[ 2x + 6 = 18 \]
\[ 2x = 12 \]
\[ x = 6 \]
Step 4: Check the other options:
If \(x = 8\), then \(2x + 6 = 22\), not 18. If \(x = 9\), the sum is 24. If \(x = 12\), the sum is 30. Only \(x = 6\) gives 18.
Final Answer:
The value of \(x\) is 6. \[ \boxed{x = 6} \]
If the length of the shadow of a tower is \(\sqrt{3}\) times its height, then the angle of elevation of the sun is:
View Solution
Step 1: Understanding the Question:A tower stands straight, its shadow lies on the ground, and the sun ray joins the tip of the tower to the tip of the shadow. This makes a right triangle. The angle of elevation is the angle between the ground and the sun ray, at the shadow tip.
Step 2: Key Formula or Approach:
In a right triangle, \(\tan\theta = \dfrac{\text{opposite side}}{\text{adjacent side}}\). Here the opposite side is the tower height and the adjacent side is the shadow length.
Step 3: Detailed Explanation:
Let the height be \(h\). Then the shadow is \(\sqrt{3}\,h\).
\[ \tan\theta = \frac{h}{\sqrt{3}\,h} = \frac{1}{\sqrt{3}} \]
We know \(\tan 30^\circ = \dfrac{1}{\sqrt{3}}\), so \(\theta = 30^\circ\).
Step 4: Check the other options:
\(\tan 90^\circ\) is not defined. \(\tan 60^\circ = \sqrt{3}\), which would mean the shadow is shorter than the tower. \(\tan 45^\circ = 1\), which would mean equal lengths. Only \(30^\circ\) fits.
Final Answer:
The angle of elevation is \(30^\circ\). \[ \boxed{30^\circ} \]
The radius of cylinder is 7 cm and height is 11 cm. The total surface area of cylinder will be:
View Solution
Step 1: Understanding the Question:We need the total surface area of a closed cylinder. That means the curved side plus the two circular ends.
Step 2: Key Formula or Approach:
\[ \text{TSA} = 2\pi r h + 2\pi r^2 = 2\pi r (r + h) \]
We take \(\pi = \dfrac{22}{7}\) because the radius is 7.
Step 3: Detailed Explanation:
Here \(r = 7\) cm and \(h = 11\) cm.
\[ \text{TSA} = 2 \times \frac{22}{7} \times 7 \times (7 + 11) \]
\[ = 44 \times 18 = 792 \text{ cm}^2 \]
Step 4: Check the other options:
748 is \(44 \times 17\), which comes from using \(r + h = 17\) by mistake. 846 and 892 do not divide evenly by 44. Only 792 matches \(44 \times 18\).
Final Answer:
The total surface area is 792 cm\(^2\). \[ \boxed{792 \text{ cm}^2} \]
Neha can complete a work in 6 days and Ishrat can complete the same work in 4 days. What will be the time taken by them to complete the same work together ?
View Solution
Step 1: Understanding the Question:Two people work on the same job at the same time. We need the time they take to finish it together.
Step 2: Key Formula or Approach:
If a person finishes a job in \(n\) days, the person does \(\dfrac{1}{n}\) of the job in one day. Add the daily shares to get the combined daily work.
Step 3: Detailed Explanation:
Neha does \(\dfrac{1}{6}\) per day and Ishrat does \(\dfrac{1}{4}\) per day.
\[ \frac{1}{6} + \frac{1}{4} = \frac{2 + 3}{12} = \frac{5}{12} \]
So together they finish \(\dfrac{5}{12}\) of the work each day.
\[ \text{Time} = \frac{12}{5} = 2\frac{2}{5} \text{ days} \]
Step 4: Check the other options:
\(1\frac{2}{5}\) days would be too fast, because the faster worker alone needs 4 days and the two together cannot be under 2 days. 3 days and 2 days do not equal \(\dfrac{12}{5}\). Only \(2\frac{2}{5}\) days is right.
Final Answer:
They finish the work together in \(2\frac{2}{5}\) days. \[ \boxed{\frac{12}{5} = 2\frac{2}{5} \text{ days}} \]
A person completes a journey of 72 km in 3 hours. How much time will he take to cover a distance of 288 km?
View Solution
Step 1: Understanding the Question:The person moves at a fixed speed. We know how long 72 km takes and need the time for 288 km.
Step 2: Key Formula or Approach:
\[ \text{Speed} = \frac{\text{Distance}}{\text{Time}}, \quad \text{Time} = \frac{\text{Distance}}{\text{Speed}} \]
Step 3: Detailed Explanation:
Speed \(= \dfrac{72}{3} = 24\) km/h.
Time for 288 km \(= \dfrac{288}{24} = 12\) hours.
Step 4: Check the other options:
6 hours would give a speed of 48 km/h and 9 hours gives 32 km/h. 15 hours gives 19.2 km/h. None of these equal 24 km/h, so only 12 hours is right.
Final Answer:
He takes 12 hours. \[ \boxed{12 \text{ hours}} \]
Which of the following statements is/are correct about irrational numbers?
(A) The sum of two rational numbers is always irrational.
(B) \(\pi\) is an irrational number.
(C) The value of \(\sqrt{49}\) is an irrational number.
(D) The value of \(\sqrt{5}\) is an irrational number.
Choose the correct answer from the options given below:
View Solution
Step 1: Understanding the Question:We must decide which of four statements are true. An irrational number cannot be written as a fraction \(\dfrac{p}{q}\) of two integers, and its decimal never ends or repeats.
Step 2: Check statement (A):
Rational numbers are closed under addition. For example \(\dfrac{1}{2} + \dfrac{1}{3} = \dfrac{5}{6}\), which is rational. The sum of two rationals is always rational, never irrational. So (A) is FALSE.
Step 3: Check statement (B):
\(\pi = 3.14159...\) is non-terminating and non-repeating, and it has been proved that it cannot be written as a fraction. So (B) is TRUE.
Step 4: Check statement (C):
\(\sqrt{49} = 7\), and 7 is a whole number, so it is rational. So (C) is FALSE.
Step 5: Check statement (D):
5 is not a perfect square, so \(\sqrt{5} = 2.236...\) never ends or repeats. So (D) is TRUE.
Step 6: Match with options:
Only (B) and (D) are correct. That is option 4. Options 1, 2 and 3 all include (A), which is false.
Final Answer:
Only statements (B) and (D) are correct. \[ \boxed{\text{(B) and (D) only}} \]
For the Arithmetic Progression : \(\frac{3}{2}, \frac{1}{2}, -\frac{1}{2}, -\frac{3}{2}, \ldots\) the common difference \(d\) is :
View Solution
Step 1: Understanding the Question:In an arithmetic progression each term is got by adding the same number to the previous term. That number is the common difference \(d\).
Step 2: Key Formula or Approach:
\[ d = a_{2} - a_{1} \]
Any two neighbouring terms will do.
Step 3: Detailed Explanation:
\[ d = \frac{1}{2} - \frac{3}{2} = -\frac{2}{2} = -1 \]
Check with the next pair: \(-\dfrac{1}{2} - \dfrac{1}{2} = -1\). And \(-\dfrac{3}{2} - \left(-\dfrac{1}{2}\right) = -1\). All gaps are the same.
Step 4: Check the other options:
-2 and -3 are too large a drop each time. +1 has the wrong sign, because the terms are going down. So only -1 works.
Final Answer:
The common difference is -1. \[ \boxed{d = -1} \]
Chronological arrangement from earlier to most recent.
(A) Maurya Empire Founded
(B) Birth of Gautam Buddha
(C) Invasion by Alexander
(D) Gupta Empire Founded
Choose the correct answer from the options given below:
View Solution
Step 1: Understanding the Question:We must put four events in order of time, oldest first. It helps to fix an approximate date for each event.
Step 2: Dates of the events:
Birth of Gautam Buddha: about 563 BCE (some sources say 566 BCE).
Invasion by Alexander: 326 BCE.
Founding of the Maurya Empire by Chandragupta Maurya: about 322 to 321 BCE.
Founding of the Gupta Empire: about 320 CE.
Step 3: Order the events:
Buddha is the earliest. Alexander (326 BCE) and the Maurya founding (about 321 BCE) are only a few years apart, and the Gupta Empire is the latest by far. Strictly the order is B, C, A, D.
Step 4: Compare with the options:
The exact order B, C, A, D is not printed in any option. Options 1 and 2 start with A, so they put Maurya before Buddha, which is clearly wrong. Option 3 puts Gupta before Alexander, which is wrong by centuries. Option 4 (B, A, C, D) has Buddha first and Gupta last and differs from the true order only in the two events that are about five years apart. So option 4 is the closest and is chosen as the answer. This item is doubtful because of that small mismatch.
Final Answer:
Option 4 (B), (A), (C), (D) is the nearest to the true order. \[ \boxed{\text{(B), (A), (C), (D)}} \]
The name of which Indian dance is a combination of expression, rhythm, melody and drama ?
View Solution
Step 1: Understanding the Question:We must find the classical dance whose name and idea join expression, rhythm, melody and drama.
Step 2: Key Concept:
The name Bharatanatyam is often explained as Bha (bhava, expression), Ra (raga, melody), Ta (tala, rhythm) and Natyam (drama). This is a common textbook breakdown of the name.
Step 3: Detailed Explanation:
Bharatanatyam comes from Tamil Nadu. It joins facial expression and hand gestures (bhava), music (raga), beat (tala) and story telling (natyam). So all four elements in the question are present in its name.
Step 4: Check the other options:
Kathak is a North Indian dance known for storytelling, spins and footwork. Kathakali is a Kerala dance drama with heavy make up and costumes. Manipuri is from Manipur and is soft, graceful and linked to Radha and Krishna. None of their names is explained by these four parts, so option 4 is right.
Final Answer:
The dance is Bharatanatyam. \[ \boxed{\text{Bharatnatyam}} \]
Who was the first ruler of Delhi Sultanate ?
View Solution
Step 1: Understanding the Question:The Delhi Sultanate was the line of Muslim rulers who governed from Delhi from the early 13th century until 1526. We need the first ruler.
Step 2: Key Fact:
After Muhammad Ghori died in 1206, his general Qutb ud-Din Aibak declared himself ruler at Lahore and later Delhi. He founded the Mamluk (Slave) dynasty, which was the first dynasty of the Delhi Sultanate.
Step 3: Detailed Explanation:
So the first ruler of the Sultanate was Qutb ud-Din Aibak, who ruled from 1206 to 1210.
Step 4: Check the other options:
Iltutmish was the son in law and successor of Aibak, so he came after him and is often called the real consolidator. Shah Jahan was a Mughal emperor of the 17th century. Dara Shikoh was the eldest son of Shah Jahan and never became emperor. So only option 3 is right.
Final Answer:
The first ruler of the Delhi Sultanate was Qutb ud-Din Aibak. \[ \boxed{\text{Qutub-U-Din-Aibak}} \]
Match List-I with List-II
| List-I Leader | List-II Movement |
|---|---|
| (A) Bal Gangadhar Tilak | (I) Punjab Nationalist Movement |
| (B) Subhash Chandra Bose | (II) Forward Block |
| (C) Mahatma Gandhi | (III) Home Rule Movement |
| (D) Lala Lajpat Rai | (IV) Civil Disobedience Movement |
Choose the correct answer from the options given below:
View Solution
Step 1: Understanding the Question:We must pair each leader in List-I with the movement he led or founded in List-II.
Step 2: Match (A):
Bal Gangadhar Tilak started the Home Rule League in Pune in 1916, so (A) matches (III).
Step 3: Match (B):
Subhash Chandra Bose founded the Forward Bloc in 1939 after leaving the Congress, so (B) matches (II).
Step 4: Match (C):
Mahatma Gandhi started the Civil Disobedience Movement in 1930 with the Dandi March, so (C) matches (IV).
Step 5: Match (D):
Lala Lajpat Rai was called the Punjab Kesari and is linked with the Punjab Nationalist Movement, so (D) matches (I).
Step 6: Compare with the options:
The full pairing is A-III, B-II, C-IV, D-I. Option 1 gives exactly this. Option 2 pairs Tilak with I, which is wrong. Option 3 also pairs Tilak with I, which is wrong. Option 4 pairs Gandhi with I, which is wrong.
Final Answer:
The correct matching is A-III, B-II, C-IV, D-I, which is option 1. \[ \boxed{\text{Option 1}} \]
Which liquid is a good conductor of electricity?
View Solution
Step 1: Understanding the Concept:A liquid conducts electricity only when it has free ions that can carry charge. Acids, bases and salt solutions have ions, so they conduct.
Step 2: Check option 1:
Distilled water has almost no dissolved salts, so it has very few ions. It is a poor conductor. So option 1 is wrong.
Step 3: Check option 2:
Lemon juice contains citric acid, which breaks into ions in water. These ions carry current, so lemon juice is a good conductor. So option 2 is right.
Step 4: Check option 3:
Sugar dissolves as whole molecules and does not form ions. So sugar solution does not conduct. Option 3 is wrong.
Step 5: Check option 4:
Kerosene is a covalent organic liquid with no ions. It does not conduct. Option 4 is wrong.
Final Answer:
Lemon juice is the liquid with free ions, so it conducts electricity. This is option 2. \[ \boxed{\text{Option 2}} \]
Which microorganism is used in curd ?
View Solution
Step 1: Understanding the Question:Curd forms when milk is fermented by bacteria. We need the correct microorganism.
Step 2: Key Concept:
Lactobacillus is a bacterium that turns the milk sugar (lactose) into lactic acid. The acid makes milk proteins clump together, forming curd.
Step 3: Check option 1:
Yeast is a fungus used in baking bread and making alcohol. It is not used to set curd. So option 1 is wrong.
Step 4: Check option 2:
Rhizobium (printed as Rhizobilium) lives in root nodules of legumes and fixes nitrogen. It has no role in curd. So option 2 is wrong.
Step 5: Check option 3:
Lactobacillus is the bacterium that sets curd, so option 3 is right.
Step 6: Check option 4:
Penicillium is a mould that gives the antibiotic penicillin. It is not used in curd. So option 4 is wrong.
Final Answer:
Curd is made by Lactobacillus, which is option 3. \[ \boxed{\text{Option 3}} \]
Which among the following metals is liquid at room temperature ?
View Solution
Step 1: Understanding the Question:We need the metal that is a liquid at room temperature, about 25 degrees Celsius.
Step 2: Key Concept:
Most metals have high melting points and are solid. Mercury is the well-known exception. Its melting point is about minus 39 degrees Celsius, so it stays liquid at room temperature.
Step 3: Check option 1:
Mercury is liquid at room temperature. So option 1 is right.
Step 4: Check option 2:
Iron melts at about 1538 degrees Celsius, so it is solid. Option 2 is wrong.
Step 5: Check option 3:
Copper melts at about 1085 degrees Celsius, so it is solid. Option 3 is wrong.
Step 6: Check option 4:
Aluminium melts at about 660 degrees Celsius, so it is solid. Option 4 is wrong.
Final Answer:
Mercury is the metal that is liquid at room temperature, option 1. \[ \boxed{\text{Option 1}} \]
Who discovered the Scattering of light?
View Solution
Step 1: Understanding the Question:The question asks who discovered the scattering of light. This refers to the Raman Effect, found in 1928.
Step 2: Key Concept:
When light passes through a transparent material, a small part of it scatters with a changed wavelength. This change is called Raman scattering. It won the Nobel Prize in Physics in 1930.
Step 3: Check option 1:
J.C. Bose worked on radio waves and plant physiology. He is not linked with light scattering. Option 1 is wrong.
Step 4: Check option 2:
C.V. Raman discovered the scattering of light, known as the Raman Effect. Option 2 is right.
Step 5: Check option 3:
Homi J. Bhabha is the father of the Indian nuclear programme. Option 3 is wrong.
Step 6: Check option 4:
A.P.J. Abdul Kalam was a missile scientist and President of India. Option 4 is wrong.
Final Answer:
The scattering of light was discovered by C.V. Raman, which is option 2. \[ \boxed{\text{Option 2}} \]
150th Birth Anniverssary of which Indian leader was celebrated by the Government of India in 2025 ?
View Solution
Step 1: Understanding the Question:We need the leader whose 150th birth anniversary fell in 2025. So the leader was born in 1875.
Step 2: Key Calculation:
2025 minus 150 equals 1875. We look for the leader born in 1875.
Step 3: Check option 1:
Sardar Vallabhbhai Patel was born on 31 October 1875. So 2025 was his 150th birth anniversary. The Government of India marked it with year long celebrations, and National Unity Day falls on 31 October. Option 1 is right.
Step 4: Check option 2:
Netaji Subhash Chandra Bose was born in 1897. His 150th anniversary is in 2047. Option 2 is wrong.
Step 5: Check option 3:
Mahatma Gandhi was born in 1869. His 150th anniversary was in 2019. Option 3 is wrong.
Step 6: Check option 4:
Lal Bahadur Shastri was born in 1904. His 150th anniversary is in 2054. Option 4 is wrong.
Final Answer:
Sardar Vallabhbhai Patel was born in 1875, so option 1 is correct. \[ \boxed{\text{Option 1}} \]
What was the main reason for Russia's starting of war against Ukraine ?
View Solution
Step 1: Understanding the Question:The question asks for the main reason Russia gave for its 2022 invasion of Ukraine.
Step 2: Background:
NATO is a military alliance of Western countries. Russia saw its eastward growth toward its borders as a threat, and Ukraine's wish to join NATO was the central issue.
Step 3: Check option 1:
Ukraine's intention to join NATO was the main stated reason for Russia's action. Option 1 is right.
Step 4: Check option 2:
Friendship with the USA existed, but it was not the direct main reason. It was part of the wider NATO worry. Option 2 is wrong as the main reason.
Step 5: Check option 3:
Ukraine buying oil from the UAE has no link to the war. Option 3 is wrong.
Step 6: Check option 4:
There was no recent change of leadership in Russia. Vladimir Putin had been in power for many years. Option 4 is wrong.
Final Answer:
The main reason was Ukraine's intention to join NATO, option 1. \[ \boxed{\text{Option 1}} \]
Select the combination of minerals which are mainly found in Rajasthan ?
(A) Zinc
(B) Copper
(C) Iron
(D) Lead
Choose the correct answer from the options given below:
View Solution
Step 1: Understanding the Question:We must pick the minerals that Rajasthan is mainly known for out of zinc, copper, iron and lead.
Step 2: Check (A) Zinc:
Rajasthan is the leading producer of zinc in India. The Zawar mines in Udaipur and the Rampura Agucha mine in Bhilwara are famous. So (A) is TRUE.
Step 3: Check (B) Copper:
The Khetri-Singhana belt in Jhunjhunu is India's well-known copper area. So (B) is TRUE.
Step 4: Check (C) Iron:
Iron ore is mainly found in Jharkhand, Odisha, Chhattisgarh and Karnataka. Rajasthan has only small deposits, so it is not a main iron state. So (C) is FALSE.
Step 5: Check (D) Lead:
Lead is found along with zinc at Zawar and Rampura Agucha, and Rajasthan is the leading lead producer. So (D) is TRUE.
Step 6: Match with options:
The true set is A, B and D. Option 4 gives exactly this. Options 1, 2 and 3 all include iron (C), which is not a main mineral of Rajasthan.
Final Answer:
Zinc, copper and lead are the main minerals of Rajasthan, so option 4 is correct. \[ \boxed{\text{Option 4: (A), (B) and (D) only}} \]
What is the main cause of the change of seasons on Earth ?
View Solution
Step 1: Understanding the Question:The question asks why Earth has seasons such as summer and winter. We need the one cause that fully explains it.
Step 2: Key Idea:
Earth's axis is tilted by about 23.5 degrees. As Earth goes around the Sun, this tilt points each hemisphere towards or away from the Sun at different times of the year.
Step 3: Check option 1.
Revolution alone does not make seasons. If the axis were not tilted, every place would get almost the same sunlight all year. So option 1 is incomplete.
Step 4: Check option 2.
Rotation on the axis gives day and night, not seasons. So option 2 is wrong.
Step 5: Check option 3.
The Moon's pull causes tides. It has no link with seasons. So option 3 is wrong.
Step 6: Check option 4.
The tilt and the revolution together change the angle and length of sunlight at a place. This gives summer, winter, spring and autumn. So option 4 is correct.
Final Answer:
Seasons change because of the tilt of Earth's axis together with its revolution around the Sun. This is option 4. \[ \boxed{\text{Option 4}} \]
Choose the combination names all of the cities through which the Ganga river passes:
(A) Delhi
(B) Rishikesh
(C) Haridwar
(D) Prayagraj
Choose the correct answer from the options given below:
View Solution
Step 1: Understanding the Question:We must pick the cities that lie on the bank of the Ganga among Delhi, Rishikesh, Haridwar and Prayagraj.
Step 2: Key Fact:
The Ganga comes out of the mountains at Rishikesh, enters the plains at Haridwar, and meets the Yamuna at Prayagraj (Allahabad). Delhi lies on the Yamuna, not on the Ganga.
Step 3: Check each city.
(A) Delhi is on the Yamuna, so it is not correct. (B) Rishikesh is on the Ganga, so it is correct. (C) Haridwar is on the Ganga, so it is correct. (D) Prayagraj is at the Ganga-Yamuna confluence, so it is correct.
Step 4: Match with options.
Only (B), (C) and (D) are correct. Option 1 and option 2 include Delhi, and option 4 includes all four cities. So option 3 is the answer.
Final Answer:
The Ganga passes through Rishikesh, Haridwar and Prayagraj, but not Delhi. This is option 3. \[ \boxed{\text{Option 3}} \]
Which neighbouring country has longest running land border with India ?
View Solution
Step 1: Understanding the Question:We need the neighbour that shares the longest land border with India.
Step 2: Key Facts:
India's land border with Bangladesh is about 4,096 km. With China it is about 3,488 km, and with Pakistan about 3,323 km.
Step 3: Check option 2 and option 4.
Pakistan (about 3,323 km) and China (about 3,488 km) are both shorter than the Bangladesh border. So they are wrong.
Step 4: Check option 3.
Sri Lanka has no land border with India. It is separated by the sea, so option 3 is wrong.
Step 5: Check option 1.
Bangladesh has the longest border, about 4,096 km. So option 1 is correct.
Final Answer:
Bangladesh shares the longest land border with India. This is option 1. \[ \boxed{\text{Option 1}} \]
Fundamental duties were adopted in the Indian Constitution through which Amendment Act ?
View Solution
Step 1: Understanding the Question:We need the Constitutional Amendment that added the Fundamental Duties.
Step 2: Key Fact:
The 42nd Amendment Act of 1976 added Part IVA and Article 51A. This followed the Swaran Singh Committee recommendations during the Emergency.
Step 3: Check option 1.
The 41st Amendment (1976) changed the retirement age of State Public Service Commission members. So it is wrong.
Step 4: Check option 3 and option 4.
The 43rd Amendment (1977) repealed some of the 42nd Amendment provisions on special courts. The 44th Amendment (1978) restored many rights and removed the right to property as a Fundamental Right. Both are wrong.
Step 5: Check option 2.
The 42nd Amendment is the one that introduced Fundamental Duties, so option 2 is correct.
Final Answer:
Fundamental Duties came through the 42nd Amendment Act. This is option 2. \[ \boxed{\text{Option 2}} \]
Which Indian Union Territory spread in more than one state ?
View Solution
Step 1: Understanding the Question:We need the Union Territory whose parts lie inside the borders of more than one state.
Step 2: Key Fact:
Puducherry is made of four separate enclaves. Puducherry and Karaikal are in or near Tamil Nadu, Mahe is in Kerala, and Yanam is in Andhra Pradesh.
Step 3: Check option 1.
Jammu and Kashmir is one compact block and is not spread across other states. So it is wrong.
Step 4: Check option 2 and option 3.
Andaman and Nicobar and Lakshadweep are island groups in the sea. They are not spread in other states. So both are wrong.
Step 5: Check option 4.
Puducherry is spread across Tamil Nadu, Kerala and Andhra Pradesh. So option 4 is correct.
Final Answer:
Puducherry has parts in several states. This is option 4. \[ \boxed{\text{Option 4}} \]
Fiscal Deficit occurs when :
View Solution
Step 1: Understanding the Concept:Fiscal deficit shows how much the government must borrow in a year to meet its spending.
Step 2: Key Formula:
Fiscal Deficit = Total Expenditure - (Revenue Receipts + Non-debt Capital Receipts). In simple words, it is spending minus income excluding borrowings.
Step 3: Check option 2.
If revenue is more than expenditure, there is a surplus, not a deficit. So option 2 is wrong.
Step 4: Check option 3.
If both are equal, the budget is balanced. So option 3 is wrong.
Step 5: Check option 4.
Spending above GDP is not the meaning of fiscal deficit and is almost never seen. So option 4 is wrong.
Step 6: Check option 1.
Spending above income, without counting borrowings, is exactly the fiscal deficit. So option 1 is correct.
Final Answer:
Fiscal deficit occurs when government expenditure exceeds its revenue excluding borrowings. This is option 1. \[ \boxed{\text{Option 1}} \]
Match List-I with List-II
| List-I Book | List-II Author |
|---|---|
| (A) Godaan | (I) Mahatma Gandhi |
| (B) Letters to my daughter | (II) Munshi Premchand |
| (C) My Experiments with Truth | (III) Khushwant Singh |
| (D) Train to Pakistan | (IV) Jawahar Lal Nehru |
View Solution
Step 1: Understanding the Question:We must match four books with their authors.
Step 2: Match each book:
(A) Godaan is a novel by Munshi Premchand, so (A) - (II). (B) Letters from a Father to His Daughter is by Jawaharlal Nehru, so (B) - (IV). (C) My Experiments with Truth is the autobiography of Mahatma Gandhi, so (C) - (I). (D) Train to Pakistan is a novel by Khushwant Singh, so (D) - (III).
Step 3: Compare with options.
The pairs are (A)-(II), (B)-(IV), (C)-(I), (D)-(III). Option 1 gives Godaan to Gandhi, which is wrong. Option 2 gives Letters to Gandhi, which is wrong. Option 4 gives Godaan to Khushwant Singh, which is wrong. Option 3 matches all four.
Final Answer:
The correct matching is A-II, B-IV, C-I, D-III. This is option 3. \[ \boxed{\text{Option 3}} \]
Choose the correct sequence with the year of launching of Indian satellites in a chronological order starting with the launching of first satellite :
(A) Mangalyaan
(B) INSAT 1A
(C) Chandrayaan-1
(D) Aryabhatta
Choose the correct answer from the options given below:
View Solution
Step 1: Understanding the Question:We must put the four missions in the order of their launch year, oldest first.
Step 2: Recall launch years:
Aryabhatta was launched in 1975 and was India's first satellite. INSAT-1A was launched in 1982. Chandrayaan-1 was launched in 2008. Mangalyaan (Mars Orbiter Mission) was launched in 2013.
Step 3: Arrange in order.
1975 (D), 1982 (B), 2008 (C), 2013 (A). So the sequence is (D), (B), (C), (A).
Step 4: Check the options.
Option 1 starts with Mangalyaan, which is the latest, so it is wrong. Option 3 starts with INSAT 1A, so it is wrong. Option 4 puts Chandrayaan-1 before INSAT 1A, which is wrong. Option 2 matches.
Final Answer:
The order is Aryabhatta, INSAT-1A, Chandrayaan-1, Mangalyaan. This is option 2. \[ \boxed{\text{Option 2}} \]
What was launched in 2007 by the Indian government to sustain productivity gains ?
View Solution
Step 1: Understanding the Question:We need the scheme started in 2007 to keep up gains in crop productivity.
Step 2: Key Fact:
The National Food Security Mission (NFSM) was launched in 2007-08. It aimed to raise production of rice, wheat and pulses through better area and productivity.
Step 3: Check the other options.
National Agricultural Security Mission, India Food Mission and India Agricultural Mission are not official government schemes. So options 1, 2 and 3 are wrong.
Step 4: Choose.
Option 4 is the real scheme, so it is correct.
Final Answer:
The National Food Security Mission was launched in 2007. This is option 4. \[ \boxed{\text{Option 4}} \]
Complete the following series by choosing the right answer:
D4 F6 H8 J10 L12.....
View Solution
Step 1: Understanding the Question:The series has a letter and a number in each term. We must find the pattern for both parts.
Step 2: Find the letter pattern.
The letters are D, F, H, J, L. Each letter jumps by 2 places (D to F, F to H, H to J, J to L). The next letter is L + 2 = N.
Step 3: Find the number pattern.
The numbers are 4, 6, 8, 10, 12. Each number increases by 2. The next number is 12 + 2 = 14.
Step 4: Join both.
The next term is N14. Option 1 (M13) uses steps of 1, which is wrong. Option 2 (N15) has the wrong number. Option 3 (O14) has the wrong letter. Option 4 is correct.
Final Answer:
The next term in the series is N14. This is option 4. \[ \boxed{\text{N14}} \]
Vishnu told Radha,'Your mother is the daughter of my grandmother.' How are Vishnu and Radha related?
View Solution
Step 1: Understanding the QuestionVishnu talks about Radha's mother. He says she is the daughter of his own grandmother. We need to find how Vishnu and Radha are related.
Step 2: Find who Radha's mother is to Vishnu
A daughter of Vishnu's grandmother is either Vishnu's mother or Vishnu's aunt (his mother's sister or his father's sister).
If she were Vishnu's mother, then Radha would be his sister and he would have said "my mother". Because he says "the daughter of my grandmother", she is his aunt.
Step 3: Find the link between Vishnu and Radha
Radha's mother is Vishnu's aunt. The children of that aunt are Vishnu's cousins. Radha is a child of that aunt, so Vishnu and Radha are cousins.
Step 4: Check the other options
Uncle-Niece would need Vishnu to be the brother of one of Radha's parents. But Radha's mother is Vishnu's aunt, not his sister.
Father-Daughter would need Vishnu to be married to Radha's mother, which nothing says.
Grandfather-Granddaughter would need a gap of two generations, but Radha and Vishnu belong to the same generation.
Final Answer:
Vishnu and Radha are cousins, option 1. \[ \boxed{\text{Cousins}} \]
If 11th January 2024 is a Thursday, what was the day on 11th January 2023 ?
View Solution
Step 1: Understanding the QuestionWe know the day for 11 January 2024 and must go back one year to 11 January 2023.
Step 2: Count the days between the dates
From 11 January 2023 to 11 January 2024 there is one full year. The year 2023 is not a leap year, and 29 February 2024 falls after 11 January 2024. So the gap is 365 days.
Step 3: Convert to odd days
A week has 7 days. \[ 365 = 7 \times 52 + 1 \]
So there is 1 odd day. The weekday moves ahead by 1 when we go forward one year.
Step 4: Go backward
11 January 2024 is a Thursday. Going back 365 days takes us one weekday back. The day before Thursday is Wednesday. So 11 January 2023 was a Wednesday.
Step 5: Check the other options
Thursday would need 0 odd days, which is only true for a gap of 364 days. Saturday and Sunday would need a shift of 2 or 3 days back, which is not the case here.
Final Answer:
11 January 2023 was a Wednesday, option 1. \[ \boxed{\text{Wednesday}} \]
Study the pattern and identify the missing number:
| 7 | 13 | 6 |
| 4 | 22 | 18 |
| 17 | ? | 7 |
View Solution
Step 1: Understanding the QuestionThe grid has three rows and three columns. Each row seems to follow the same rule. We must find the rule from the complete rows and use it on the row with the missing number.
Step 2: Study row 1
Row 1 is 7, 13, 6. Adding the first and last numbers gives 7 + 6 = 13, which is the middle number.
Step 3: Study row 2
Row 2 is 4, 22, 18. Again 4 + 18 = 22, which is the middle number. So the rule holds in both complete rows.
Step 4: Apply the rule to row 3
Row 3 is 17, ?, 7. The middle number is 17 + 7 = 24.
Step 5: Check the other options
23, 25 and 21 do not equal 17 + 7, so they break the rule that worked for both rows above.
Final Answer:
The missing number is 24, option 4. \[ \boxed{24} \]
If ACEGI is written as 13579, what will BDFHJ be written in the same code ?
View Solution
Step 1: Understanding the QuestionEach letter of ACEGI is written as a number in the code 13579. We must find the rule and use it for BDFHJ.
Step 2: Find the rule
Write the position of each letter in the alphabet: A = 1, C = 3, E = 5, G = 7, I = 9. These are exactly the numbers in the code 13579. So every letter is replaced by its position number.
Step 3: Apply the rule to BDFHJ
B = 2, D = 4, F = 6, H = 8, J = 10. Writing them one after another gives 2, 4, 6, 8, 10, that is 246810.
Step 4: Check the other options
12345 uses the first five numbers and does not match the letter positions.
24689 has 9 in place of 10, so J is coded wrongly.
235710 is not the position pattern at all.
Final Answer:
BDFHJ is written as 246810, option 2. \[ \boxed{246810} \]
Vijay travels a distance of 5 km in the south. Then he turns to his right. After walking 5 km, he again turns to his right and walks 5 km. In which direction is he from his starting place ?
View Solution
Step 1: Understanding the QuestionVijay makes three legs of 5 km each. He turns right after the first and second leg. We track his position from the start.
Step 2: First leg
He walks 5 km south. He is now 5 km south of the start.
Step 3: Second leg
He is facing south. When you face south, your right hand points west. So he turns to the west and walks 5 km. He is now 5 km south and 5 km west of the start.
Step 4: Third leg
Now he faces west. When you face west, your right hand points north. He walks 5 km north, which cancels the 5 km he went south. He is now 0 km south and 5 km west of the start.
Step 5: Read the direction
Vijay is exactly 5 km to the west of the starting point. So he is in the west direction.
Step 6: Check the other options
North-East, South and North would need some north-south or east gap left after the third leg, but the north-south gap became zero and he moved to the west side, not east.
Final Answer:
Vijay is in the west direction from the start, option 1. \[ \boxed{\text{West}} \]
A clock becomes fast by 15 second in every 2 hours. If it is set correct at 5 P.M. on Sunday, what will be the time on clock on Monday at 9 A.M. ?
View Solution
Step 1: Understanding the QuestionThe clock gains 15 seconds for every 2 hours of real time. It is right at 5 P.M. on Sunday. We need the time it shows at 9 A.M. on Monday.
Step 2: Find the real time passed
From 5 P.M. Sunday to 5 A.M. Monday is 12 hours. From 5 A.M. to 9 A.M. is 4 more hours. The total is 16 hours.
Step 3: Find the number of 2-hour blocks
\[ \frac{16}{2} = 8 \]
So there are 8 blocks of 2 hours.
Step 4: Find the total time gained
\[ 8 \times 15 = 120 \text{ seconds} = 2 \text{ minutes} \]
Step 5: Find the time on the clock
The clock is ahead by 2 minutes. When the real time is 9:00 A.M., the clock shows 9:02 A.M.
Step 6: Check the other options
9:03 would need 180 seconds, that is 12 blocks or 24 hours. 9:04 and 9:05 need even more. These do not fit 16 hours.
Final Answer:
The clock shows 9:02 A.M., option 1. \[ \boxed{9:02 \text{ A.M.}} \]
In which option the given figure can be embedded.


View Solution
Step 1: Understanding the QuestionThe given figure is a small triangle with one long line that continues beyond the triangle. One side of the triangle is vertical, and the other two sides meet at a point on the left. We must find the option where this exact shape is hidden.
Step 2: Describe the given figure
The triangle points to the left. Its right side is vertical. The upper slanted side is extended beyond the vertical side towards the upper right.
Step 3: Check option 1
The right part has a horizontal line from the centre to the right edge. Its diagonals end exactly at the corners, so no diagonal goes past a vertical side. There is no triangle with a vertical side and an extended slanted side. So option 1 is wrong.
Step 4: Check option 2
This has one long rising diagonal, a horizontal line and a vertical line crossing at the middle. No left pointing triangle with a vertical side is formed. So option 2 is wrong.
Step 5: Check option 3
Here only a small slanting stroke crosses the middle of a plus sign. It is too short to make the given triangle. So option 3 is wrong.
Step 6: Check option 4
The two diagonals cross at the centre. The vertical line on the right cuts both diagonals. The centre and the two cut points form a triangle that points left with a vertical right side. The upper diagonal continues past the vertical line to the corner, which is the extended line in the given figure. So option 4 is correct.
Final Answer:
The given figure is hidden in option 4. \[ \boxed{\text{Option 4}} \]
Select the figure which will complete the problem figure matrix.


View Solution
Step 1: Understanding the Question:The matrix has three filled boxes and one empty box. We must find the figure that fills the empty box.
Step 2: Count the circles:
Top left has 1 circle, top right has 3 circles, bottom left has 2 circles, bottom right is unknown.
Step 3: Find the pattern:
Going from the left box to the right box, the number of circles is multiplied by 3 (1 × 3 = 3). The same rule must hold in the bottom row: 2 × 3 = 6 circles.
Step 4: Match with the options:
Option 4 shows 6 circles (two columns of three). Options 1, 2 and 3 show 3, 4 and 5 circles.
Final Answer:
The missing figure is option 4.
\[ \boxed{\text{Option 4}} \]
Match List-I with List-II

Choose the correct answer from the options given below:
View Solution
Step 1: Understanding the Question:List-I shows three letters in a row. List-II shows mirror images. In a mirror image, the order of the row is reversed left to right, and each letter is also flipped sideways.
Step 2: Key Idea:
The letter A is symmetric, so its mirror image looks like A. The letters B and C are not symmetric, so they look flipped. To get a mirror image, write the row backwards and flip each letter.
Step 3: Match (A) A B C:
Write the row backwards: C, B, A. Flip the letters: flipped C, flipped B, A. This is (II). So (A) - (II).
Step 4: Match (B) A C B:
Backwards: B, C, A. Flipped: flipped B, flipped C, A. This is (I). So (B) - (I).
Step 5: Match (C) B A C:
Backwards: C, A, B. Flipped: flipped C, A, flipped B. This is (IV). So (C) - (IV).
Step 6: Match (D) B C A:
Backwards: A, C, B. Flipped: A, flipped C, flipped B. This is (III). So (D) - (III).
Step 7: Check the options:
Only option 1 gives (A) - (II), (B) - (I), (C) - (IV), (D) - (III). Options 2, 3 and 4 each have at least one wrong pair.
Final Answer:
The correct matching is A-II, B-I, C-IV, D-III, which is option 1. \[ \boxed{\text{Option 1}} \]
Find the odd one out:
View Solution
Step 1: Understanding the Question:We have four numbers and three of them share a property that the fourth does not. We must find the number that does not fit.
Step 2: Key Idea:
Check whether each number is a prime number. A prime has only two factors, 1 and itself.
Step 3: Test each number:
23 has no factor other than 1 and 23, so it is prime. 43 is not divisible by 2, 3, 5 or 7, so it is prime. 73 is not divisible by 2, 3, 5 or 7, so it is prime. 93 has digit sum 9 + 3 = 12, which is divisible by 3, so 93 = 3 x 31 and it is not prime.
Step 4: Check the options:
Options 1, 2 and 3 are primes. Option 4 is composite, so it is the odd one out.
Final Answer:
93 is the odd one out because it is not prime. \[ \boxed{93} \]
Vijay is 13th from the right end in a row of 45 boys. What is his position from the left end ?
View Solution
Step 1: Understanding the Question:Vijay stands in a row of 45 boys. We know his place counted from the right end. We need his place counted from the left end.
Step 2: Key Formula:
Position from left = Total number of boys - Position from right + 1.
Step 3: Calculation:
Position from left = 45 - 13 + 1.
\[ 45 - 13 + 1 = 33 \]
Step 4: Check the options:
32nd would need 45 - 32 + 1 = 14th from the right. 34th would give 12th from the right. 35th would give 11th from the right. Only 33rd gives 13th from the right.
Final Answer:
Vijay is 33rd from the left end. \[ \boxed{33^{\text{rd}}} \]
Find the missing number in the series:
5 15 9 ? 11 33 13 39
View Solution
Step 1: Understanding the Question:The series looks like it is made of pairs of numbers. We must find the pattern in each pair and use it to get the missing number.
Step 2: Split into pairs:
Group the numbers as (5, 15), (9, ?), (11, 33), (13, 39).
Step 3: Find the rule:
In the pair (5, 15), 15 = 5 x 3. In the pair (11, 33), 33 = 11 x 3. In the pair (13, 39), 39 = 13 x 3. So the second number in each pair is 3 times the first.
Step 4: Apply the rule:
For the pair (9, ?), the missing number is 9 x 3 = 27.
Step 5: Check the options:
9 and 18 are not 3 times 9. 36 is 4 times 9. Only 27 fits.
Final Answer:
The missing number is 27. \[ \boxed{27} \]
A, B, C, D, E and F are sitting on a bench. E and F are sitting in the centre. A and B are sitting on the two corners. C is sitting to the left of A. Who is sitting to the right of B ?
View Solution
Step 1: Understanding the Question:Six people sit in a line on a bench. There are 6 places from left to right. We use the clues to fix each person.
Step 2: Place the corners and centre:
A and B sit on the two ends, which are places 1 and 6. E and F sit in the centre, which are places 3 and 4.
Step 3: Use the clue about C:
C is to the left of A. If A were at place 1 (the left end), nothing could be on its left. So A must be at place 6, and B is at place 1. C sits to the left of A, so C is at place 5.
Step 4: Find the last person:
The only person left is D, and the only place left is place 2. So the order is B, D, E/F, E/F, C, A.
Step 5: Answer:
The person to the right of B (at place 1) is the one at place 2, which is D. So option 1 is right. C, B and A do not sit next to B on its right.
Final Answer:
D sits to the right of B. \[ \boxed{D} \]
Which of the following answer figure can be constructed from the given problem figure ?


View Solution
Step 1: Understanding the Question:The problem figure has four small squares. We must find which answer figure can be built from these pieces.
Step 2: Study the problem figure:
The figure holds exactly four equal small squares placed in a 2 by 2 arrangement. So the answer figure must be made of four equal square parts, with nothing else added.
Step 3: Check option 1:
Option 1 is a square cut by two diagonals. It has 4 triangular parts, not squares. So it cannot be built.
Step 4: Check option 2:
Option 2 is a rectangle cut into 2 parts. It has 2 parts, not 4 squares. So it cannot be built.
Step 5: Check option 3:
Option 3 has both diagonals and a cross, so it has 8 triangular parts. This does not match 4 squares.
Step 6: Check option 4:
Option 4 is a square divided by a horizontal and a vertical line into 4 equal square cells. Put the four small squares together in a 2 by 2 block and you get exactly this figure. So option 4 is right.
Final Answer:
Option 4 can be constructed from the four squares. \[ \boxed{\text{Option 4}} \]
CUET UG 2026 Exam Pattern
| Parameter | Details |
|---|---|
| Exam Name | Common University Entrance Test (CUET UG) 2026 |
| Conducting Body | National Testing Agency (NTA) |
| Exam Mode | Computer-Based Test (CBT) |
| Exam Duration | 60 minutes per test |
| Total Sections | 3 (Languages, Domain Subjects, General Test) |
| Question Type | Multiple Choice Questions (MCQs) |
| Questions per Test | 50 questions (all compulsory) |
| Marking Scheme | +5 for correct, -1 for incorrect |
| Maximum Marks | 250 marks per test |
| Maximum Subject Choices | 5 subjects in total |
| Syllabus Base | Class 12 NCERT (mainly for Domain Subjects) |

















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