NEET 2023 Chemistry Question Paper with Solutions PDF H3

NEET Questions

• 1.

  A thin horizontal disc is rotating about a vertical axis passing through its fixed centre \(O\). Its angular momentum is \(L_A\) and \(L_B\) computed about points \(A\) and \(B\), respectively, where \(OB=2\times OA\). The value of \[ \frac{L_A}{L_B} \] is:

  

  • \(2\)
  • \(\frac14\)
  • \(\frac12\)
  • \(1\)
  View Solution

  ---

• 2.

  10 मिलियन कोशिकाओं की एक population पर विचार करें। यदि प्रति व्यक्ति जन्म दर 0.002 (प्रति इकाई समय) और प्रति व्यक्ति मृत्यु दर 0.002 (प्रति इकाई समय) दी गई है, तो 10 पीढ़ियों के बाद कोशिकाओं की अपेक्षित संख्या ________ होगी।

  • 10 मिलियन
  • 100 मिलियन
  • 1 मिलियन
  • 5 मिलियन
  View Solution

  ---

• 3.

  In an adiabatic expansion, the temperature of one mole of an ideal monoatomic gas \((\gamma=\frac{5}{3})\) decreases from \(60\,\text{K}\) to \(50\,\text{K}\). The work done by the gas in the process is: (Take the universal gas constant as \(R=8.3\,\text{J mol}^{-1}\text{K}^{-1}\))

  • \(166\,\text{J}\)
  • \(41.5\,\text{J}\)
  • \(83\,\text{J}\)
  • \(124.5\,\text{J}\)
  View Solution

  ---

• 4.

  For a salt XY, which is a strong electrolyte, the plot of \(\Lambda_m\) versus \(\sqrt{c}\) has a slope of \(-90.0\text{ S cm}^2\text{ mol}^{-3/2}\text{ L}^{1/2}\) at \(298\text{ K}\). At \(0.01\text{ M}\) concentration of XY, the value of \(\Lambda_m\) is \(145.0\text{ S cm}^2\text{ mol}^{-1}\). The limiting molar conductivity of \(\text{Y}^-\) ion (\(\lambda^\circ_{\text{Y}^-}\), in \(\text{S cm}^2\text{ mol}^{-1}\)) at \(298\text{ K}\) will be (Given: \(\lambda^\circ_{\text{X}^+} = 74.0\text{ S cm}^2\text{ mol}^{-1}\))

  • \(76.0\)
  • \(80.0\)
  • \(100.0\)
  • \(90.0\)
  View Solution

  ---

• 5.

  निम्नलिखित आरेख, ऊर्ध्वाधर ऊपर फेंकी गई एक गेंद का ऊपर जाते हुए और वापस नीचे गिरते हुए वेग (v) का समय (t) के साथ परिवर्तन को दर्शाते हैं। निम्नलिखित में से कौन-सा/से आरेख सही है/हैं? 
   

  

  • केवल C
    
  • केवल A और E
    
  • केवल D
    
  • केवल B
    
  View Solution

  ---

• 6.

  The numbers \(17.0145\) and \(21.0235\) were rounded to three figures after the decimal point. The resulting numbers, respectively, are

  • \(17.015\) and \(21.024\)
  • \(17.014\) and \(21.023\)
  • \(17.015\) and \(21.023\)
  • \(17.014\) and \(21.024\)
  View Solution