JEE Main 2023 Chemistry April 10 Shift 1 Question Paper PDF Download

Download the official JEE Main 2023 Chemistry April 10 Shift 1 Question Paper PDF with Solutions and Answer Key right here! Supercharge your JEE Main 2025 preparation with this NTA-approved previous year question paper, available via the link below. The JEE Main Chemistry Question Paper includes Section A with 20 MCQs and Section B with 10 numerical-type questions—answer all from Section A and any 5 from Section B. Rated moderate by aspirants, with emphasis on organic and physical chemistry, this free JEE Main 2023 question paper PDF is your ultimate tool to master the JEE Main exam pattern.

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JEE Main 2023 Question Paper With Solutions For Chemistry

Question 1:

The major product 'P' formed in the given reaction is:

Correct Answer: (1) Option 1

View Solution

Question 2:

Prolonged heating is avoided during the preparation of ferrous ammonium sulphate to:

Prevent hydrolysis
Prevent reduction
Prevent breaking
Prevent oxidation

Correct Answer: (4) Prevent oxidation
View Solution

Question 3:

Identify the correct order of reactivity for the following pairs towards the respective mechanism:

(A), (C), and (D) only
(A), (B), and (D) only
(B), (C), and (D) only
(A), (B), (C), and (D)

Correct Answer: (4) (A), (B), (C), and (D)
View Solution

Question 4:

The ∆H° for the reaction C(graphite) + 1/2 O₂(g) → CO(g) is:

(x − 2y)/2
(x + 2y)/2
(2x − y)/2
(2y − x)

Correct Answer: (1) (x − 2y)/2
View Solution

Question 5:

Using column chromatography, a mixture of two compounds 'A' and 'B' was separated. 'A' eluted first. This indicates 'B' has:

High R_f, weaker adsorption
High R_f, stronger adsorption
Low R_f, stronger adsorption
Low R_f, weaker adsorption

Correct Answer: (3) Low R_f, stronger adsorption
View Solution

Question 6:

Lime reacts exothermally with water to give 'A' which has low solubility in water. Aqueous solution of 'A' is often used for the test of CO₂, where insoluble 'B' is formed. If 'B' is further reacted with CO₂, a soluble compound is formed. 'A' is:

Quick lime
Slaked lime
White lime
Lime water

Correct Answer: (2) Slaked lime
View Solution

Question 7:

Match List I with List II:

List I: Industry
List II: Waste Generated

Steel plants - Slag
Thermal power plants - Fly ash
Fertilizer industries - Gypsum
Paper mills - Bio-degradable wastes

Correct Answer: (4) (A)-(III), (B)-(II), (C)-(I), (D)-(IV)
View Solution

Question 8:

Suitable reaction condition for preparation of Methyl phenyl ether is:

Benzene, MeBr
PhO^-Na⁺, MeOH
Ph-Br, MeO^-Na⁺
PhO^-Na⁺, MeBr

Correct Answer: (4) PhO^-Na⁺, MeBr
View Solution

Question 9:

The one that does not stabilize 2° and 3° structures of proteins is:

H-bonding
–S–S– linkage
van der Waals forces
–O–O– linkage

Correct Answer: (4) –O–O– linkage
View Solution

Question 10:

The compound which does not exist is:

PbEt₄
BeH₂
NaO₂
(NH₄)₂BeF₄

Correct Answer: (3) NaO₂
View Solution

Question 11:

Given below are two reactions, involved in the commercial production of dihydrogen (H₂). The two reactions are carried out at temperature T₁ and T₂, respectively:

C(s) + H₂O(g) → CO(g) + H₂ (T₁)
CO(g) + H₂O(g) → CO₂(g) + H₂ (T₂)

The temperatures T₁ and T₂ are correctly related as:

T₁ = T₂
T₁ < T₂
T₁ > T₂
T₁ = 100 K, T₂ = 1270 K

Correct Answer: (3) T₁ > T₂
View Solution

Question 12:

The enthalpy change for the adsorption process and micelle formation respectively are:

∆H_ads < 0 and ∆H_mic < 0
∆H_ads > 0 and ∆H_mic < 0
∆H_ads < 0 and ∆H_mic > 0
∆H_ads > 0 and ∆H_mic > 0

Correct Answer: (3) ∆H_ads < 0 and ∆H_mic > 0
View Solution

Question 13:

The pair from the following pairs having both compounds with net non-zero dipole moment is:

cis-butene, trans-butene
Benzene, anisidine
CH₂Cl₂, CHCl₃
1,4-Dichlorobenzene, 1,3-Dichlorobenzene

Correct Answer: (3) CH₂Cl₂, CHCl₃
View Solution

Question 14:

Which of the following is used as a stabilizer during the concentration of sulphide ores?

Xanthates
Fatty acids
Pine oils
Cresols

Correct Answer: (4) Cresols
View Solution

Question 15:

Which of the following statements are correct?

(A) The M³⁺/M²⁺ reduction potential for iron is greater than manganese.
(B) The higher oxidation states of first-row d-block elements get stabilized by oxide ion.
(C) Aqueous solution of Cr²⁺ can liberate hydrogen from dilute acid.
(D) Magnetic moment of V²⁺ is observed between 4.4-5.2 BM.

(C), (D) only
(B), (C) only
(A), (B), (D) only
(A), (B) only

Correct Answer: (2) (B), (C) only
View Solution

Question 16:

Given below are two statements:

Statement I: Aqueous solution of K₂Cr₂O₇ is preferred as a primary standard in volumetric analysis over Na₂Cr₂O₇ aqueous solution.
Statement II: K₂Cr₂O₇ has a higher solubility in water than Na₂Cr₂O₇.

In the light of the above statements, choose the correct answer:

Statement I is false but Statement II is true
Statement I is true but Statement II is false
Both Statement I and Statement II are true
Both Statement I and Statement II are false

Correct Answer: (2) Statement I is true but Statement II is false
View Solution

Question 17:

The octahedral diamagnetic low spin complex among the following is:

[CoF₆]³⁻
[CoCl₆]³⁻
[Co(NH₃)₆]³⁺
[NiCl₄]²⁻

Correct Answer: (3) [Co(NH₃)₆]³⁺
View Solution

Question 18:

Isomeric amines with molecular formula C₈H₁₁N give the following tests:

(P) Can be prepared by Gabriel phthalimide synthesis.
(Q) Reacts with Hinsberg’s reagent to give a solid insoluble in NaOH.
(R) Reacts with HONO followed by β-naphthol in NaOH to give a red dye.

Isomer (P), (Q), and (R), respectively, are:

Correct Answer: (2) Option 2

View Solution

Question 19:

The number of molecules and moles in 2.8375 litres of O₂ at STP are respectively:

7.527 × 10²² and 0.125 mol
1.505 × 10²³ and 0.250 mol
7.527 × 10²³ and 0.125 mol
7.527 × 10²² and 0.250 mol

Correct Answer: (1) 7.527 × 10²² and 0.125 mol
View Solution

Question 20:

Match List I with List II:

List I: Polymer
List II: Classification

(A) Nylon-2-Nylon-6 - Biodegradable polymer
(B) Buna-N - Synthetic rubber
(C) Urea-formaldehyde resin - Thermosetting polymer
(D) Dacron - Polyester

(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
(A)-(II), (B)-(I), (C)-(IV), (D)-(III)
(A)-(IV), (B)-(I), (C)-(III), (D)-(II)
(A)-(II), (B)-(III), (C)-(I), (D)-(IV)

Correct Answer: (4) (A)-(II), (B)-(III), (C)-(I), (D)-(IV)
View Solution

Question 21:

If the degree of dissociation of an aqueous solution of weak monobasic acid is determined to be 0.3, then the observed freezing point will be % higher than the expected/theoretical freezing point. (Nearest integer)

Correct Answer: 30%
View Solution

Question 22:

In the following reactions, the total number of oxygen atoms in X and Y is:
Na₂O + H₂O → 2X
Cl₂O₇ + H₂O → 2Y

Correct Answer: 5
View Solution

Question 23:

The sum of lone pairs present on the central atom of the interhalogens IF₅ and IF₇ is:

Correct Answer: 1
View Solution

Question 24:

The number of bent-shaped molecule(s) from the following is:
N₃⁻, NO₂⁻, I₃⁻, O₃, SO₂

Correct Answer: 3 View Solution

Question 25:

The number of correct statement(s) involving equilibria in physical form from the following is:
(1) Equilibrium is possible only in a closed system at a given temperature.
(2) Both the opposing processes occur at the same rate.
(3) When equilibrium is attained at a given temperature, the value of all its parameters becomes constant.
(4) For dissolution of solids in liquids, the solubility is constant at a given temperature.

Correct Answer: 3
View Solution

Question 26:

At constant temperature, a gas is at a pressure of 940.3 mm Hg. The pressure at which its volume decreases by 40% is:

Correct Answer: 1567 mm Hg
View Solution

Question 27:

FeO₄²⁻ + 2.2V → Fe³⁺, Fe³⁺ + 0.7V → Fe²⁺, Fe²⁺ -0.45V → Fe°. E°_{FeO4²⁻/Fe²⁺} is x × 10⁻³V. The value of x is:

Correct Answer: 1825
View Solution

Question 28:

A molecule undergoes two independent first-order reactions whose respective half-lives are 12 min and 3 min. If both reactions are occurring, the time taken for 50% consumption of the reactant is:

Correct Answer: 2 minutes
View Solution

Question 29:

The number of incorrect statement(s) about the black body from the following is:
(1) Emits or absorbs energy in the form of electromagnetic radiation.
(2) Frequency distribution of the emitted radiation depends on temperature.
(3) At a given temperature, intensity vs frequency curve passes through a maximum value.
(4) The maximum of the intensity vs frequency curve is at a higher frequency at higher temperature compared to that at lower temperature.

Correct Answer: 0
View Solution

Question 30:

In potassium ferrocyanide, there are pairs of electrons in the t_2g set of orbitals:

Correct Answer: 3
View Solution

JEE Main 2023 Chemistry Paper Analysis April 10 Shift 1

JEE Main 2023 Chemistry Paper Analysis for the exam scheduled on April 10 Shift 1 is available here. Candidates can check subject-wise paper analysis for the exam scheduled on April 10 Shift 1 here along with the topics with the highest weightage.

JEE Main 2023 Chemistry Paper Analysis April 10 Shift 1

JEE Main 2023 Chemistry Question Paper Pattern

Feature	Question Paper Pattern
Examination Mode	Computer-based Test
Exam Language	13 languages (English, Hindi, Assamese, Bengali, Gujarati, Kannada, Malayalam, Marathi, Odia, Punjabi, Tamil, Telugu, and Urdu)
Exam Duration	3 hours
Sectional Time Limit	None
Chemistry Marks	100 marks
Total Number of Questions Asked	20 MCQs + 10 Numerical Type Questions
Total Number of Questions to be Answered	20 MCQs + 5 Numerical Type Questions
Marking Scheme	+4 for each correct answer
Negative Marking	-1 for each incorrect answer

Also Check:

JEE Main Chemistry Question Paper Pattern	JEE Main Chapter-wise Weightage

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JEE Main 2023 Question Paper PDF For Chemistry (April 10 Shift 1 ) - Download with Solutions

Download JEE Main 2023 Question Paper PDF For Chemistry with Solutions (April 10 Shift 1)

JEE Main 2023 Question Paper With Solutions For Chemistry

JEE Main 2023 Chemistry Paper Analysis April 10 Shift 1

JEE Main 2023 Chemistry Question Paper Pattern

JEE Main Previous Year Question Paper

JEE Main Questions

2.
Let the sum of the first n terms of an A.P. be $3n^2 + 5n$. Then the sum of squares of the first 10 terms of the A.P. is:

3.
The coefficient of \(x^{48}\) in \[ (1+x) + 2(1+x)^2 + 3(1+x)^3 + \cdots + 100(1+x)^{100} \] is equal to

4.
$2.8 \times 10^{-3}$ mol of CO$_2$ is left after removing $10^{21}$ molecules from its $x$ mg sample. The mass of CO$_2$ taken initially is: Given: $N_A = 6.02 \times 10^{23}\,\text{mol}^{-1}$

5.
Let $a_1,a_2,a_3,a_4$ be an A.P. of four terms such that each term of the A.P. and its common difference are integers. If $a_1+a_2+a_3+a_4=48$ and $a_1^2a_2a_3a_4+1^4=361$, then the largest term of the A.P. is equal to

6.
Find sum up to 8 terms of the series
\[ \frac{1^3}{1}+\frac{1^3+2^3}{1+3}+\frac{1^3+2^3+3^3}{1+3+5}+\cdots \]

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Download JEE Main 2023 Question Paper PDF For Chemistry with Solutions (April 10 Shift 1)

JEE Main 2023 Question Paper With Solutions For Chemistry

JEE Main 2023 Chemistry Paper Analysis April 10 Shift 1

JEE Main 2023 Chemistry Question Paper Pattern

JEE Main Previous Year Question Paper

JEE Main Questions

2.Let the sum of the first n terms of an A.P. be $3n^2 + 5n$. Then the sum of squares of the first 10 terms of the A.P. is:

3.The coefficient of \(x^{48}\) in \[ (1+x) + 2(1+x)^2 + 3(1+x)^3 + \cdots + 100(1+x)^{100} \] is equal to

4.$2.8 \times 10^{-3}$ mol of CO$_2$ is left after removing $10^{21}$ molecules from its $x$ mg sample. The mass of CO$_2$ taken initially is: Given: $N_A = 6.02 \times 10^{23}\,\text{mol}^{-1}$

5.Let $a_1,a_2,a_3,a_4$ be an A.P. of four terms such that each term of the A.P. and its common difference are integers. If $a_1+a_2+a_3+a_4=48$ and $a_1^2a_2a_3a_4+1^4=361$, then the largest term of the A.P. is equal to

6.Find sum up to 8 terms of the series \[ \frac{1^3}{1}+\frac{1^3+2^3}{1+3}+\frac{1^3+2^3+3^3}{1+3+5}+\cdots \]

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2.
Let the sum of the first n terms of an A.P. be $3n^2 + 5n$. Then the sum of squares of the first 10 terms of the A.P. is:

3.
The coefficient of \(x^{48}\) in \[ (1+x) + 2(1+x)^2 + 3(1+x)^3 + \cdots + 100(1+x)^{100} \] is equal to

4.
$2.8 \times 10^{-3}$ mol of CO$_2$ is left after removing $10^{21}$ molecules from its $x$ mg sample. The mass of CO$_2$ taken initially is: Given: $N_A = 6.02 \times 10^{23}\,\text{mol}^{-1}$

5.
Let $a_1,a_2,a_3,a_4$ be an A.P. of four terms such that each term of the A.P. and its common difference are integers. If $a_1+a_2+a_3+a_4=48$ and $a_1^2a_2a_3a_4+1^4=361$, then the largest term of the A.P. is equal to

6.
Find sum up to 8 terms of the series
\[ \frac{1^3}{1}+\frac{1^3+2^3}{1+3}+\frac{1^3+2^3+3^3}{1+3+5}+\cdots \]