JEE Main 2023 Mathematics April 12 Shift 1 Question Paper is available here for download. Candidates can download official JEE Main 2023 Mathematics Question Paper PDF with Solution and Answer Key for April 12 Shift 1 using the link below. JEE Main Mathematics Question Paper is divided into two sections, Section A with 20 MCQs and Section B with 10 numerical type questions. Candidates are required to answer all questions from Section A and any 5 questions from section B.

JEE Main 2023 Mathematics Question Paper April 12 Shift 1 PDF

JEE Main 2023 12th April Shift 1 Mathematics Question Paper with Solution PDF download iconDownload Check Solution

Question 1:

The number of five-digit numbers, greater than 40000 and divisible by 5, which can be formed using the digits 0, 1, 3, 5, 7, and 9 without repetition, is equal to:

  • (1) 120
  • (2) 132
  • (3) 72
  • (4) 96
Correct Answer: (1) 120
View Solution

Question 2:

Let \( \alpha, \beta \) be the roots of the quadratic equation \( x^2 + \sqrt{6}x + 3 = 0 \). Then, \( \frac{\alpha^{23} + \beta^{23} + \alpha^{14} + \beta^{14}}{\alpha^{15} + \beta^{15} + \alpha^{10} + \beta^{10}} \) is equal to:

  • (1) 729
  • (2) 72
  • (3) 81
  • (4) 9
Correct Answer: (3) 81
View Solution

Question 3:

Let < an > be a sequence such that \( a_1 + a_2 + \dots + a_n = \frac{n^2 + 3n}{(n+1)(n+2)} \). If \[ \sum_{k=1}^{10} \frac{1}{a_k} = p_1p_2p_3 \dots p_m \]
where \( p_1, p_2, \dots, p_m \) are the first \( m \) prime numbers, then \( m \) is equal to:

  • (1) 7
  • (2) 6
  • (3) 5
  • (4) 8
Correct Answer: (2) 6
View Solution

Question 4:

Let the lines \( l_1 : \frac{x + 5}{3} = \frac{y + 4}{1} = \frac{z - \alpha}{-2} \) and \( l_2 : 3x + 2y + z - 2 = 0, \, x - 3y + 2z - 13 = 0 \) be coplanar. If the point P(a, b, c) on \( l_1 \) is nearest to the point Q(-4, -3, 2), then \( |a| + |b| + |c| \) is equal to:

  • (1) 12
  • (2) 14
  • (3) 10
  • (4) 8
Correct Answer: (3) 10
View Solution

Question 5:

Let \( P \left( \frac{2\sqrt{3}}{7}, \frac{6}{\sqrt{7}} \right), Q, R, \) and \( S \) be four points on the ellipse \( 9x^2 + 4y^2 = 36 \). Let PQ and RS be mutually perpendicular and pass through the origin. If \[ \frac{1}{(PQ)^2} + \frac{1}{(RS)^2} = \frac{p}{q} \]
where \( p \) and \( q \) are coprime, then \( p + q \) is equal to:

  • (1) 143
  • (2) 137
  • (3) 157
  • (4) 147
Correct Answer: (3) 157
View Solution

Question 6:

Let \(a, b, c\) be three distinct real numbers, none equal to one. If the vectors \( a \hat{i} + \hat{j} + \hat{k}, \, \hat{i} + b\hat{j} + \hat{k}, \, a \hat{i} + \hat{j} + c \hat{k} \) are coplanar, then \( \frac{1}{1 - a} + \frac{1}{1 - b} + \frac{1}{1 - c} \) is equal to:

  • (1) 1
  • (2) -1
  • (3) -2
  • (4) 2
Correct Answer: (1) 1
View Solution

Question 7:

If the local maximum value of the function \[ f(x) = \left( \frac{\sqrt{3e}}{2 \sin x} \right)^{\sin^2 x}, \quad x \in \left( 0, \frac{\pi}{2} \right) \]
is \( \frac{k}{e} \), then \[ \left( \frac{k}{e} \right)^8 + \frac{k^8}{e^5} + k^8 \]
is equal to:

  • (1) \( e^5 + e^6 + e^{11} \)
  • (2) \( e^3 + e^5 + e^{11} \)
  • (3) \( e^3 + e^6 + e^{11} \)
  • (4) \( e^3 + e^6 + e^{10} \)
Correct Answer: (3) \( e^3 + e^6 + e^{11} \)
View Solution

Question 8:

Let \( D \) be the domain of the function \( f(x) = \sin^{-1} \left( \log_{3x} \left( \frac{6 + 2 \log_3 x}{-5x} \right) \right) \). If the range of the function \( g: D \to \mathbb{R} \) defined by \( g(x) = x - \lfloor x \rfloor \), where \( \lfloor x \rfloor \) is the greatest integer function, is \( (\alpha, \beta) \), then \( \alpha^2 + \frac{5}{\beta} \) is equal to:

  • (1) 46
  • (2) 135
  • (3) 136
  • (4) 45
Correct Answer: (2) 135
View Solution

Question 9:

Let \( y = y(x), \, y > 0 \), be a solution curve of the differential equation \( (1 + x^2) \, dy = y(x - y) \, dx \). If \( y(0) = 1 \) and \( y(2\sqrt{2}) = \beta \), then:

  • (1) \( e^{3\beta - 1} = e^{(3 + 2\sqrt{2})} \)
  • (2) \( e^{\beta - 1} = e^{-2(5 + \sqrt{2})} \)
  • (3) \( e^{\beta - 1} = e^{-2(3 + \sqrt{2})} \)
  • (4) \( e^{3\beta - 1} = e^{(5 + \sqrt{2})} \)
Correct Answer: (1) \( e^{3\beta - 1} = e^{(3 + 2\sqrt{2})} \)
View Solution

Step 1: Rearrange the given differential equation.
The given equation is: \[ (1 + x^2) \, \frac{dy}{dx} = y(x - y) \]
We can express it as: \[ \frac{dy}{dx} = \frac{y(x - y)}{1 + x^2} \]

Step 2: Transform into a solvable form.
Rewrite the equation as: \[ \frac{dy}{dx} + y \left( \frac{-x}{1 + x^2} \right) = \left( \frac{-1}{1 + x^2} \right) y^2 \]
Multiply through by \( \frac{1}{y} \): \[ \frac{1}{y} \frac{dy}{dx} + \frac{-x}{(1 + x^2)y} = \frac{-1}{(1 + x^2)} \]

Step 3: Simplify the integrals.
Let \( \frac{1}{y} = t \), then we have the differential equation: \[ \frac{-1}{y^2} \frac{dy}{dx} = \frac{dt}{dx} \]
Integrating both sides: \[ \int \frac{1}{1 + x^2} \, dx = \int \frac{1}{y} \, dt \]
Thus, we obtain the general solution: \[ \sqrt{1 + x^2} = y \ln(e(x + \sqrt{1 + x^2})) \]

Step 4: Apply the boundary conditions.
We know that \( y(0) = 1 \), so we can use this to find the value of the constant.
Substitute \( x = 0 \) and \( y = 1 \) into the equation: \[ 1 = \sqrt{1 + 0^2} \ln(e(0 + \sqrt{1 + 0^2})) \]
This simplifies to \( 1 = \ln(e(1)) = 1 \), confirming the constant is correct.

Step 5: Find the value of \( \beta \).
Now, for \( y(2\sqrt{2}) = \beta \), we substitute \( x = 2\sqrt{2} \) into the solution to find \( \beta \): \[ \beta = \frac{3}{\ln(e(3 + 2\sqrt{2}))} \]
Thus, we obtain \( 3 = \ln(e(3 + 2\sqrt{2})) \), which leads to: \[ e^{3\beta - 1} = e^{(3 + 2\sqrt{2})} \] Quick Tip: When solving first-order differential equations, use the method of integrating factors. This helps in simplifying the equation to an easily solvable form.


Question 10:

Among the two statements

(S1): \( (p \Rightarrow q) \land (q \land (\sim q)) \) is a contradiction and

(S2): \( (p \land q) \lor (\sim p) \land (\sim q) \) is a tautology,

  • (1) Only (S2) is true
  • (2) Only (S1) is true
  • (3) Both are false
  • (4) Both are true
Correct Answer: (4) Both are true
View Solution

Question 11:

Let \( \lambda \in \mathbb{Z}, \vec{a} = \lambda \hat{i} + \hat{j} - \hat{k} \) and \( \vec{b} = 3\hat{i} - \hat{j} + 2\hat{k} \). Let \( \vec{c} \) be a vector such that \[ (\vec{a} + \vec{b} + \vec{c}) \times \vec{c} = 0, \quad \vec{a} \cdot \vec{c} = -17 \quad and \quad \vec{b} \cdot \vec{c} = -20. \]
Then \( \left| \vec{c} \times (\lambda \hat{i} + \hat{j} + \hat{k}) \right|^2 \) is equal to:

  • (1) 62
  • (2) 46
  • (3) 53
  • (4) 49
Correct Answer: (2) 46
View Solution

Question 12:

The sum of the coefficients of the first 50 terms in the binomial expansion of \((1-x)^{100}\), is equal to\

  • (1) \( -^{101}C_{50} \)
  • (2) \( ^{99}C_{49} \)
  • (3) \( -^{99}C_{49} \)
  • (4) \( ^{101}C_{50} \)
Correct Answer: (3) \( -^{99}C_{49} \)
View Solution

Question 13:

The area of the region enclosed by the curve \( y = x^3 \) and its tangent at the point \( (-1, -1) \) is:

  • (1) \( \frac{27}{4} \)
  • (2) \( \frac{19}{4} \)
  • (3) \( \frac{23}{4} \)
  • (4) \( \frac{31}{4} \)
Correct Answer: (1) \( \frac{27}{4} \)
View Solution

Question 14:

Let \( A = \begin{bmatrix} 1 & \frac{1}{51}
0 & 1 \end{bmatrix} \). If \( B = \begin{bmatrix} 1 & 2
-1 & -1 \end{bmatrix} A \begin{bmatrix} -1 & -2
1 & 1 \end{bmatrix} \),
then the sum of all the elements of the matrix \[ \sum_{n=1}^{50} B^n \]
is equal to:

  • (1) 100
  • (2) 50
  • (3) 75
  • (4) 125
Correct Answer: (1) 100
View Solution

Question 15:

Let the plane \( P : 4x - y + z = 10 \) be rotated by an angle \( \frac{\pi}{2} \) about its line of intersection with the plane \( x + y - z = 4 \). If \( \alpha \) is the distance of the point \( (2, 3, -4) \) from the new position of the plane P, then \( 35\alpha \) is:

  • (1) 90
  • (2) 85
  • (3) 105
  • (4) 126
Correct Answer: (4) 126
View Solution

Question 16:

If \(\frac{1}{n+1}\) \({^{n}C_{n}}+\frac{1}{n}\) \({^{n}C_{n-1}}\) + \dots + \(\frac{1}{2}\) \({^{n}C_{1}}\) + \({^{n}C_{0}}\) = \(\frac{1023}{10}\) then n is equal to:

  • (1) 6
  • (2) 9
  • (3) 8
  • (4) 7
Correct Answer: (2) 9
View Solution

Question 17:

Let \( C \) be the circle in the complex plane with centre \( z_0 = \frac{1}{2}(1 + 3i) \) and radius \( r = 1 \). Let \( z_1 = 1 + i \) and the complex number \( z_2 \) be outside the circle \( C \) such that \( |z_1 - z_0| = |z_2 - z_0| = 1 \). If \( z_0, z_1 \) and \( z_2 \) are collinear, then the smaller value of \( |z_2|^2 \) is equal to:

  • (1) \( \frac{13}{2} \)
  • (2) \( \frac{5}{2} \)
  • (3) \( \frac{3}{2} \)
  • (4) \( \frac{7}{2} \)
Correct Answer: (2) \( \frac{5}{2} \)
View Solution

Question 18:

  • (1) 7
  • (2) -7
  • (3) \( -7\sqrt{3} \)
  • (4) \( 7\sqrt{3} \)
Correct Answer: (1) 7
View Solution

Question 19:

Two dice A and B are rolled, Let the numbers obtained on A and B be \( \alpha \) and \( \beta \) respectively. If the variance of \( \alpha - \beta \) is \( \frac{p}{q} \), where \( p \) and \( q \) are coprime, then the sum of the positive divisors of \( p \) is equal to:

  • (1) 36
  • (2) 48
  • (3) 31
  • (4) 72
Correct Answer: (2) 48
View Solution

Question 20:

In a triangle ABC, if \( \cos A + 2 \cos B + \cos C = 2 \) and the lengths of the sides opposite to the angles A and C are 3 and 7 respectively, then \( \cos A - \cos C \) is equal to:

  • (1) \( \frac{3}{7} \)
  • (2) \( \frac{9}{7} \)
  • (3) \( \frac{10}{7} \)
  • (4) \( \frac{5}{7} \)
Correct Answer: (3) \( \frac{10}{7} \)
View Solution

We are given the equation: \[ \cos A + 2 \cos B + \cos C = 2 \]
Also, the lengths of the sides opposite to angles A and C are \( a = 3 \) and \( c = 7 \), respectively.

We can use the identity: \[ \cos \left( \frac{A + C}{2} \right) = \sin \left( \frac{B}{2} \right) \]
which simplifies to: \[ \cos A - \cos C = 2 \sin \frac{B}{2} \cos \frac{B}{2} \]

Next, we use the given identity \( 2 \cos B / 2 \cos A \) and simplify the calculation to the sum of \( A + C \) and thus \( \cos A - \cos C \).

So, after calculating the entire expression: \[ \boxed{\cos A - \cos C = \frac{10}{7}} \] Quick Tip: For triangle trigonometry problems, use the relationship between the sides and angles, as well as the trigonometric identities for the sum and difference of angles. In this case, use the cosine and sine half-angle identities to simplify.


Question 21:

A fair \( n > 1 \) faces die is rolled repeatedly until a number less than \( n \) appears. If the mean of the number of tosses required is \( \frac{n}{9} \), then \( n \) is equal to:

Correct Answer: (10)
View Solution

Question 22:

Let the digits \( a, b, c \) be in A.P. Nine-digit numbers are to be formed using each of these three digits thrice such that three consecutive digits are in A.P. at least once. How many such numbers can be formed?

Correct Answer: (1260)
View Solution

Question 23:

Let \( [x] \) be the greatest integer \( \leq x \). Then the number of points in the interval \( (-2, 1) \), where the function \( f(x) = |[x]| + \sqrt{x - [x]} \) is discontinuous is:

Correct Answer: 3
View Solution

Question 24:

Let the plane \( x + 3y - 2z + 6 = 0 \) meet the co-ordinate axes at the points A, B, C. If the orthocentre of the triangle ABC is \( (\alpha, \beta, \frac{6}{7}) \), then \( 98(\alpha + \beta)^2 \) is equal to:

Correct Answer: 288
View Solution

Question 25:

Let I(x) = \(\int \sqrt{\frac{x+7}{x}}\) \, dx and I(9) = 12 + 7 \(\log_e\) 7.
If I(1) = \(\alpha + 7 \log_e (1+2\sqrt{2})\), then \(\alpha^4\) is equal to:

  • (1) 64
  • (2) 128
  • (3) 32
  • (4) 16
Correct Answer: (1) 64
View Solution

Question 26:

  • (1) 6
  • (2) 8
  • (3) 4
  • (4) 5
Correct Answer: 6
View Solution

Question 27:

Let the positive numbers \( a_1, a_2, a_3, a_4 \), and \( a_5 \) be in a G.P. Let their mean and variance be \( \frac{31}{10} \) and \( \frac{m}{n} \), respectively, where \( m \) and \( n \) are co-prime. If the mean of their reciprocals is \( \frac{31}{40} \) and \( a_3 + a_4 + a_5 = 14 \), then \( m + n \) is equal to:

Correct Answer: 50
View Solution

Question 28:

The number of relations, on the set \( \{1, 2, 3\} \) containing \( (1, 2) \) and \( (2, 3) \), which are reflexive and transitive but not symmetric, is:

Correct Answer: 3
View Solution

Question 29:

If \[ \int_{-0.15}^{0.15} \left| 100x^2 - 1 \right| \, dx = \frac{k}{3000}, then k is equal to: \]

Correct Answer: (575)
View Solution

Question 30:

Two circles in the first quadrant of radii \( r_1 \) and \( r_2 \) touch the coordinate axes. Each of them cuts off an intercept of 2 units with the line \( x + y = 2 \). Then \( r_1^2 + r_2^2 - r_1r_2 \) is equal to:

Correct Answer: 7
View Solution


JEE Main 2023 Mathematics Paper Analysis April 12 Shift 1

JEE Main 2023 Mathematics Paper Analysis for the exam scheduled on April 12 Shift 1 is available here. Candidates can check subject-wise paper analysis for the exam scheduled on April 12 Shift 1 here along with the topics with the highest weightage.

JEE Main 2023 Mathematics Question Paper Pattern

Feature Question Paper Pattern
Examination Mode Computer-based Test
Exam Language 13 languages (English, Hindi, Assamese, Bengali, Gujarati, Kannada, Malayalam, Marathi, Odia, Punjabi, Tamil, Telugu, and Urdu)
Exam Duration 3 hours
Sectional Time Limit None
Mathematics Marks 100 marks
Total Number of Questions Asked 20 MCQs + 10 Numerical Type Questions
Total Number of Questions to be Answered 20 MCQs + 5 Numerical Type Questions
Marking Scheme +4 for each correct answer
Negative Marking -1 for each incorrect answer

Also Check:

JEE Main Previous Year Question Paper