JEE Main 2023 Mathematics April 13 Shift 2 Question Paper is available here for download. Candidates can download official JEE Main 2023 Mathematics Question Paper PDF with Solution and Answer Key for April 13 Shift 2 using the link below. JEE Main Mathematics Question Paper is divided into two sections, Section A with 20 MCQs and Section B with 10 numerical type questions. Candidates are required to answer all questions from Section A and any 5 questions from section B.

JEE Main 2023 Mathematics Question Paper April 13 Shift 2 PDF

JEE Main 2023 April 13 Shift 2​ Mathematics Question Paper with Solution PDF download iconDownload Check Solution

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JEE Main 2023 Mathematics Questions with Solutions

Section – A

Question 1:

The area of the region \{(x,y): x^2 \leq y \leq |x^2 - 4|, y \geq 1\ \text{ is:

  • (1) \(\frac{3}{4} (4\sqrt{2} + 1) \)
  • (2) \(\frac{4}{3} (4\sqrt{2} - 1) \)
  • (3) \(\frac{3}{4} (4\sqrt{2} - 1) \)
  • (4) \(\frac{4}{3} (4\sqrt{2} + 1) \)
Correct Answer: \textbf{(2)} \(\frac{4}{3} (4\sqrt{2} - 1) \)
View Solution

The given problem asks to find the area of a region bounded by the equations of curves. The expression for the required area involves integrating two functions over the given limits.

The area can be represented as:
\[ Required area = \int_{-2}^{2} \sqrt{y} \, dy + \int_{-2}^{2} \sqrt{4 - y} \, dy = \frac{4}{3} \left[ 4\sqrt{2} - 1 \right] \] Quick Tip: To find the area between curves, set up the integral based on the limits of integration derived from the boundaries of the region. Ensure the expressions under the integral sign are correctly derived from the curves.


Question 2:


If \[ \lim_{x \to 0} \frac{e^{x} - \cos(bx) - cx}{1 - \cos(2x)} = 2, \]
then \( 5a^2 + b^2 \) is equal to:

  • (1) 76
  • (2) 72
  • (3) 64
  • (4) 68
Correct Answer:(4) 68
View Solution

Question 3:


The line, that is coplanar to the line \[ \frac{x+1}{-3} = \frac{y-2}{1} = \frac{z-5}{5}, \]
is:

  • (1) \(\frac{x+1}{-3} = \frac{y-2}{2} = \frac{z-5}{5}\)
  • (2) \(\frac{x+1}{-3} = \frac{y-2}{-2} = \frac{z-5}{5}\)
  • (3) \(\frac{x-1}{-2} = \frac{y-2}{2} = \frac{z-5}{4}\)
  • (4) \(\frac{x-1}{-2} = \frac{y-2}{5} = \frac{z-5}{4}\)
Correct Answer:(1)
View Solution

Question 4:


The plane, passing through the points \( (0, -1, 2) \) and \( (-1, 2, 1) \) and parallel to the line passing through \( (5,1,-7) \) and \( (1,-1,-1) \), also passes through the point

  • (1) \( (0, 5, -2) \)
  • (2) \( (-2, 5, 0) \)
  • (3) \( (2, 0, 1) \)
  • (4) \( (1, -2, 1) \)
Correct Answer:(2)
View Solution

Question 5:


Let for a triangle ABC, \[ \overrightarrow{AB} = -2\hat{i} + \hat{j} + 3\hat{k}, \quad \overrightarrow{CB} = \hat{i} + \hat{j} + \hat{k}, \quad \overrightarrow{CA} = 4\hat{i} + 3\hat{j} + 4\hat{k} \]
If \( \lambda \) = 0 and the area of triangle ABC is 5 \sqrt{6, then \( CB \) is equal to:

  • (1) 108
  • (2) 60
  • (3) 54
  • (4) 120
Correct Answer:(2)
View Solution

Question 6:


Let for \[ A = \begin{pmatrix} 1 & 2 & 3
1 & 2 & 3
1 & 1 & 2 \end{pmatrix}, \quad |A| = 2. \quad If \quad |2 \, adj (2A)| = 32, \quad then \quad 3n + \alpha is equal to: \]

  • (1) 10
  • (2) 9
  • (3) 12
  • (4) 11
Correct Answer:(4)
View Solution

Question 7:


The range of \( f(x) = 4 \sin \left( \frac{x^2}{x^2 + 1} \right) \) is:

  • (1) \( (0, \infty) \)
  • (2) \( (0, \pi) \)
  • (3) \( [0, 2\pi] \)
  • (4) \( [0, \pi] \)
Correct Answer:(3)
View Solution

Question 8:


Let \( a_1, a_2, a_3, \dots \) be a G.P. of increasing positive numbers. Let the sum of its 6th and 8th terms be 2 and the product of its 3rd and 5th terms be \( \frac{1}{9} \). Then \( 6a_6 + a_6 a_8 \) is equal to:

  • (1) 2
  • (2) 3
  • (3) \( 3\sqrt{5} \)
  • (4) \( 2\sqrt{5} \)
Correct Answer:(2) 3
View Solution

Question 9:


If the system of equations \[ 2x + y = -5
2x - 5y + z = -9
x + 2y - 5z = 7 \]
has infinitely many solutions, then \( (x + y)^2 + (y + z)^2 \) is equal to:

  • (1) 904
  • (2) 916
  • (3) 912
  • (4) 920
Correct Answer:(2) 916
View Solution

Question 10:


The statement \[ (p \rightarrow q) \rightarrow (r \rightarrow q) \equiv (p \vee q) \rightarrow (r \vee q) \]
is equivalent to:

  • (1) \( p \vee q \)
  • (2) \( p \rightarrow (q \rightarrow p) \)
  • (3) \( p \vee (q \vee r) \)
  • (4) \( p \vee q \rightarrow r \)
Correct Answer:(1) \( p \vee q \)
View Solution

Question 11:


Let \( S = \{ z \in \mathbb{C} : z = i(z^2 + Re(z)) \} \). Then \( \sum_{z \in S} |z|^2 \) is equal to:

  • (1) \( 4 \)
  • (2) \( \frac{7}{2} \)
  • (3) \( 3 \)
  • (4) \( \frac{5}{2} \)
Correct Answer:(1) 4
View Solution

Question 12:


Let \( \alpha, \beta \) be the roots of the equation \( x^2 - \sqrt{5}x + 2 = 0 \). Then \( \alpha^4 + \beta^4 \) is equal to:

  • (1) \( -64 \)
  • (2) \( -128 \)
  • (3) \( 64 \)
  • (4) \( -256 \)
Correct Answer:(3) \( 64 \)
View Solution

Question 13:


Let \( |a| = 2, |b| = 3 \) and the angle between the vectors \( a \) and \( b \) be \( \frac{\pi}{4} \). Then \( |a + 2b| \times |2a - 3b| \) is equal to:

  • (1) 482
  • (2) 841
  • (3) 882
  • (4) 441
Correct Answer:\textbf{(3)} 882
View Solution

Question 14:


The value of \[ \int_{0}^{\frac{\pi}{4}} \frac{e^x}{(e^x + \tan^2 x)} \, dx \]
is:

  • (1) 25
  • (2) 51
  • (3) 50
  • (4) 49
Correct Answer:\textbf{(3)} 50
View Solution

Question 15:


The coefficient of \( x^2 \) in the expansion of \[ \left( 2x^2 - \frac{1}{3x^3} \right)^5 \]
is:

  • (1) \( \frac{80}{9} \)
  • (2) 8
  • (3) 9
  • (4) \( \frac{26}{3} \)
Correct Answer:\textbf{(1)} \( \frac{80}{9} \)
View Solution

Question 16:


The random variable X follows binomial distribution B (n, p), for which the difference of the mean and the variance is 1. If \[ 1^{2}P(X = x) - 2P(X = 3X - 1), \quad then \quad np(X)^{2} is equal to \]

  • (1) 16
  • (2) 11
  • (3) 12
  • (4) 15
Correct Answer:\textbf{(2)} 11
View Solution

Question 17:


Let the centre of a circle C be (\alpha, \beta) and its radius r < 8. Let \(3x + 4y - 24\) and \(3x - 4y - 32\) be two tangents and \(4x + 3y = 1\) be a normal to C. Then the value of (\alpha - \beta) is equal to:

  • (1) 5
  • (2) 6
  • (3) 7
  • (4) 9
Correct Answer:\textbf{(3)} 7
View Solution

Question 18:


Let N be the foot of perpendicular from the point P(1, -2, 3) on the line passing through the points (4, 5, 8) and (1, -7, -5). Then the distance of N from the plane \( 2x - 2y + z = 5 \) is:

  • (1) 6
  • (2) 7
  • (3) 9
  • (4) 8
Correct Answer: \textbf{(2)} 7
View Solution

Question 19:


All words, with or without meaning, are made using all the letters of the word MONDAY. These words are written in a dictionary with serial numbers. The serial number of the word MONDAY is:

  • (1) 328
  • (2) 327
  • (3) 324
  • (4) 326
Correct Answer:\textbf{(2)} 327
View Solution

Question 20:


Let \( \alpha, \beta \) be the centroid of the triangle formed by the lines \( 15x + y = 82 \), \( 6x - 5y = -4 \), and \( 9x + 4y = 17 \). Then at \( \alpha \) and \( \beta \) are the roots of the equation:

  • (1) \( x^2 - 13x + 42 = 0 \)
  • (2) \( x^2 - 10x + 25 = 0 \)
  • (3) \( x^2 - 7x + 12 = 0 \)
  • (4) \( x^2 - 14x + 48 = 0 \)
Correct Answer:\textbf{(1)} \( x^2 - 13x + 42 = 0 \)
View Solution

Section – B

Question 21:

Let \( A = \{-4, -3, 2, 0, 1, 3, 4\} \) and \( R = \{(a, b) : a \in A, b = |a| or a = b\} \) be a relation on \( A \). Then the minimum number of elements that must be added to the relation \( R \) so that it becomes reflexive and symmetric, is:

Correct Answer:\textbf{(7)}
View Solution

We are given a relation \( R = \{(a, b): a \in A, b = |a| or a = b\} \) on \( A \), where \( A = \{-4, -3, 2, 0, 1, 3, 4\} \).

The relation is initially defined as follows:
\[ R = \{(-4, -4), (-3, 3), (3, -3), (2, 2), (0, 0), (1, 1), (4, 4)\} \]

For \( R \) to be reflexive, we need to ensure that every element in \( A \) is related to itself. The elements \( -4, 3, 1 \) are already related to themselves, so we need to add the following pairs to make the relation reflexive: \[ \{(-3, -3), (2, 2), (0, 0)\} \]

Next, for \( R \) to be symmetric, if \( (a, b) \) is in \( R \), then \( (b, a) \) must also be in \( R \). The pairs that are not symmetric are \( (-4, 3) \) and \( (3, -4) \), so we need to add the pair \( (-3, -3) \).

The total number of pairs added to make the relation reflexive and symmetric is \( 7 \). Quick Tip: For a relation to be reflexive, each element in the set should be related to itself. For a relation to be symmetric, if an element is related to another, the reverse must also hold.


Question 22:


Let \( f = \left( \sum_{k=1}^{\infty} \sin^k x \right) \left( \sum_{k-1} \sin^k x \right) \cos x dx \in N \). Then \( f_{11} \) is equal to:

Correct Answer:\textbf{(3)} 50
View Solution

Question 23:


If \( y = y(x) \) is the solution of the differential equation \[ \frac{dy}{dx} = \frac{4x}{(x - 1)^{2}} - \frac{x^2 - 2}{(x - 1)^{3}} such that y(2) = \frac{2}{9} \log_2 \left( 2 + \sqrt{5} \right) \]
and \( y(x) = \alpha \log \left( \sqrt{x + \beta} \right) + \gamma \cdot \sqrt{x} - \frac{1}{x} \), then \( \alpha \beta \gamma \) is equal to:

Correct Answer:\textbf{(6)}
View Solution

Question 24:


Total numbers of 3-digit numbers that are divisible by 6 and can be formed by using the digits 1, 2, 3, 4, 5 with repetition, is:

Correct Answer:\textbf{(2)} 8
View Solution

Question 25:


The remainder, when \(7^{110}\) is divided by 17, is \underline{\hspace{3cm.

Correct Answer:\textbf{(1)} 12
View Solution

Question 26:


Let \( f(x) = \sum_{k=1}^{\infty} x^k \), where \( x \in \mathbb{R} \) and \( f(2) = 119 \). Then \( f(2) - f(1) \) is equal to _______________.

Correct Answer:\textbf{(2)} 10
View Solution

N/A


Question 27:


For \( x \in (-1, 1) \), the number of solutions of the equation \( \sin x = 2 \tan x \) is equal to_______________.

Correct Answer:\textbf{(2)} 2 solutions
View Solution

Question 28:


The mean and standard deviation of the marks of 10 students were found to be 50 and 12 respectively. Later, it was observed that two marks 20 and 25 were wrongly read as 45 and 50 respectively. Then the correct variance is \hspace{3cm}.

Correct Answer:\textbf{(2)} 269
View Solution

Question 29:


The foci of a hyperbola are \( (\pm 2, 0) \) and its eccentricity is \( \frac{3}{2} \). A tangent, perpendicular to the line \( 2x + 3y - 6 = 0 \), is drawn at a point in the first quadrant on the hyperbola. If the intercepts made by the tangent on the \( x \)- and \( y \)-axes are \( a \) and \( b \) respectively, then \( |a| + |b| \) is equal to \underline{\hspace{3cm.

Correct Answer:\textbf{(1)} 12
View Solution

Question 30:


Let \( [\alpha] \) denote the greatest integer \( \leq \alpha \). Then \( [\sqrt{1}] + [\sqrt{2}] + [\sqrt{3}] + \dots + [\sqrt{20}] \) is equal to \underline{\hspace{3cm.

Correct Answer:\textbf{(1)} 825
View Solution


JEE Main 2023 Mathematics Paper Analysis April 13 Shift 2

JEE Main 2023 Mathematics Paper Analysis for the exam scheduled on April 13 Shift 2 is available here. Candidates can check subject-wise paper analysis for the exam scheduled on April 13 Shift 2 here along with the topics with the highest weightage.

JEE Main 2023 Mathematics Question Paper Pattern

Feature Question Paper Pattern
Examination Mode Computer-based Test
Exam Language 13 languages (English, Hindi, Assamese, Bengali, Gujarati, Kannada, Malayalam, Marathi, Odia, Punjabi, Tamil, Telugu, and Urdu)
Exam Duration 3 hours
Sectional Time Limit None
Mathematics Marks 100 marks
Total Number of Questions Asked 20 MCQs + 10 Numerical Type Questions
Total Number of Questions to be Answered 20 MCQs + 5 Numerical Type Questions
Marking Scheme +4 for each correct answer
Negative Marking -1 for each incorrect answer

Also Check:

JEE Main Previous Year Question Paper