JEE Main 2023 Mathematics Question Paper Feb 1 Shift 2 is updated here after the conclusion of the exam. Candidates can download JEE Main 2023 Mathematics Question Paper PDF with Answer Key for Feb 1 Shift 2 using the link below. JEE Main Mathematics Question Paper is divided into two sections, Section A with 20 MCQs and Section B with 10 numerical type questions. Candidates are required to answer all questions from Section A and any 5 questions from section B.
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JEE Main 2023 Mathematics Question Paper Feb 1 Shift 2- Download PDF
| JEE Main 2023 Feb 1 Shift 2 Mathematics Question Paper with Solution PDF | Check Solution |

JEE Main 2023 Feb 1 Shift 2 Mathematics Question Paper with Solution
Question 1:
The sum \( \sum_{n=1}^{\infty} \frac{2n^2 + 3n + 4}{(2n)!} \) is equal to:
View Solution
Provided sum is: \[ \sum_{n=1}^{\infty} \frac{2n^2 + 3n + 4}{(2n)!}. \]
Step 1: Split the Terms of the Numerator
Rewrite the numerator \( 2n^2 + 3n + 4 \) as: \[ 2n^2 + 3n + 4 = 2n(2n-1) + 8n + 8. \]
Therefore, the sum becomes: \[ \sum_{n=1}^{\infty} \frac{2n^2 + 3n + 4}{(2n)!} = \frac{1}{2} \sum_{n=1}^{\infty} \frac{2n(2n-1)}{(2n)!} + 2 \sum_{n=1}^{\infty} \frac{n}{(2n-1)!} + 4 \sum_{n=1}^{\infty} \frac{1}{(2n)!}. \]
Step 2: Simplify Each Term Using Series Expansions
For the first term: \[ \sum_{n=1}^{\infty} \frac{2n(2n-1)}{(2n)!} = \sum_{n=1}^{\infty} \frac{1}{(2n-2)!}. \]
This is the series expansion of \( e + \frac{1}{e} \), so: \[ \frac{1}{2} \sum_{n=1}^{\infty} \frac{2n(2n-1)}{(2n)!} = \frac{e + \frac{1}{e}}{2}. \]
For the second term: \[ \sum_{n=1}^{\infty} \frac{1}{(2n-1)!} = e - \frac{1}{e}. \]
Therefore: \[ 2 \sum_{n=1}^{\infty} \frac{n}{(2n-1)!} = e - \frac{1}{e}. \]
For the third term: \[ \sum_{n=1}^{\infty} \frac{1}{(2n)!} = \frac{e + \frac{1}{e}}{2}. \]
Therefore: \[ 4 \sum_{n=1}^{\infty} \frac{1}{(2n)!} = 2 \left(e + \frac{1}{e}\right). \]
Step 3: Combine All Terms
Combine all terms: \[ \frac{1}{2} \sum_{n=1}^{\infty} \frac{2n(2n-1)}{(2n)!} + 2 \sum_{n=1}^{\infty} \frac{n}{(2n-1)!} + 4 \sum_{n=1}^{\infty} \frac{1}{(2n)!} = \frac{e + \frac{1}{e}}{4} + e - \frac{1}{e} + 2 \left(e + \frac{1}{e}\right). \]
Simplify: \[ Sum = \frac{e + \frac{1}{e}}{4} + e - \frac{1}{e} + 2e + \frac{2}{e}. \]
Combine terms: \[ Sum = \frac{13e}{4} + \frac{5}{4e} - 4. \]
Conclusive Answer: The sum is \( \frac{13e}{4} + \frac{5}{4e} - 4 \) (Option 2). Quick Tip: For sums involving factorials, try to decompose the terms into known series expansions like \( e^x \) or related expressions. This makes it easier to compute and simplify the results.
Let \( S = \{x \in \mathbb{R} : 0 < x < 1 and 2 \tan^{-1}\left(\frac{1-x}{1+x}\right) = \cos^{-1}\left(\frac{1-x^2}{1+x^2}\right)\} \). If \( n(S) \) denotes the number of elements in \( S \), then:
(3) \( n(S) = 1 \) and the element in \( S \) is less than \( \frac{1}{2} \).
View Solution
Let \( \vec{a} = 2\hat{i} - 7\hat{j} + 5\hat{k} \), \( \vec{b} = \hat{i} + \hat{k} \), and \( \vec{c} = \hat{i} + 2\hat{j} - 3\hat{k} \) be three given vectors. If \( \vec{r} \) is a vector such that \( \vec{r} \times \vec{a} = \vec{c} \times \vec{a} \) and \( \vec{r} \cdot \vec{b} = 0 \), then \( |\vec{r}| \) is equal to:
If \( A = \frac{1}{2} \begin{bmatrix} 1 & \sqrt{3}
-\sqrt{3} & 1 \end{bmatrix} \), then:
Two dice are thrown independently. Let \( A \) be the event that the number appeared on the 1st die is less than the number appeared on the 2nd die, \( B \) be the event that the number appeared on the 1st die is even and that on the 2nd die is odd, and \( C \) be the event that the number appeared on the 1st die is odd and that on the 2nd die is even. Then:
(1) The number of favourable cases of the event \( (A \cup B) \cap C \) is 6.
View Solution
Which of the following statements is a tautology?
The number of integral values of \( k \), for which one root of the equation \( 2x^2 - 8x + k = 0 \) lies in the interval \( (1, 2) \) and its other root lies in the interval \( (2, 3) \), is:
Let \( f : \mathbb{R} - \{0, 1\} \to \mathbb{R} \) be a function such that \( f(x) + f\left(\frac{1}{1-x}\right) = 1 + x \). Then \( f(2) \) is equal to:
Let the plane \( P \) pass through the intersection of the planes \( 2x + 3y - z = 2 \) and \( x + 2y + 3z = 6 \), and be perpendicular to the plane \( 2x + y - z + 1 = 0 \). If \( d \) is the distance of \( P \) from the point \((-7, 1, 1)\), then \( d^2 \) is equal to:
Let \( a, b \) be two real numbers such that \( ab < 0 \). If the complex number \( \frac{1 + ai}{b + i} \) is of unit modulus and \( a + ib \) lies on the circle \( |z - 1| = |2z| \), then a possible value of \( \frac{1 + \lfloor a \rfloor}{4b} \), where \( \lfloor t \rfloor \) is the greatest integer function, is:
The sum of the absolute maximum and minimum values of the function \( f(x) = |x^2 - 5x + 6| - 3x + 2 \) in the interval \([-1, 3]\) is equal to:
Let \( P(S) \) denote the power set of \( S = \{1, 2, 3, \dots, 10\} \). Define the relations \( R_1 \) and \( R_2 \) on \( P(S) \) as \( A R_1 B \) if \[ (A \cap B^c) \cup (B \cap A^c) = \varnothing, \]
and \( A R_2 B \) if \[ A \cup B^c = B \cup A^c, \]
for all \( A, B \in P(S) \). Then:
The area of the region given by \(\{(x, y) : xy \leq 8, \, 1 \leq y \leq x^2\}\) is:
Let \( \alpha x = \exp(x^\beta y^\gamma) \) be the solution of the differential equation \( 2x^2 y \, dy - (1 - xy^2) \, dx = 0 \), \( x > 0 \), \( y(2) = \sqrt{\ln_e 2} \). Then \( \alpha + \beta - \gamma \) equals:
The value of the integral \[ \int_{-\frac{\pi}{4}}^{\frac{\pi}{4}} \frac{x + \frac{\pi}{4}}{2 - \cos 2x} \, dx is: \]
Let \( 9 = x_1 < x_2 < \dots < x_7 \) be in an A.P. with common difference \( d \). If the standard deviation of \( x_1, x_2, \dots, x_7 \) is \( 4 \) and the mean is \( \overline{x} \), then \( \overline{x} + x_6 \) is equal to:
For the system of linear equations \( ax + y + z = 1 \), \( x + ay + z = 1 \), \( x + y + az = \beta \), which one of the following statements is NOT correct?
(1) It has infinitely many solutions if \( \alpha = 2 \) and \( \beta = -1 \).
View Solution
Let \( \vec{a} = 5\hat{i} - \hat{j} - 3\hat{k} \) and \( \vec{b} = \hat{i} + 3\hat{j} + 5\hat{k} \) be two vectors. Then which one of the following statements is TRUE?
Let \( P(x_0, y_0) \) be the point on the hyperbola \( 3x^2 - 4y^2 = 36 \), which is nearest to the line \( 3x + 2y = 1 \). Then \( \sqrt{2} \, (y_0 - x_0) \) is equal to:
If \( y(x) = x^x, \, x > 0 \), then \( y''(2) - 2y'(2) \) is equal to:
The total number of six-digit numbers, formed using the digits \(4, 5, 9\) only and divisible by 6, is ____.
Number of integral solutions to the equation \( x + y + z = 21 \), where \( x \geq 1, y \geq 3, z \geq 4 \), is ____.
The line \( x = 8 \) is the directrix of the ellipse \( E: \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \) with the corresponding focus \( (2, 0) \). If the tangent to \( E \) at the point \( P \) in the first quadrant passes through the point \( \left( 0, 4\sqrt{3} \right) \) and intersects the \( x \)-axis at \( Q \), then \( (3PQ)^2 \) is equal to ____.
If the x-intercept of a focal chord of the parabola \( y^2 = 8x + 4y + 4 \) is \( 3 \), then the length of this chord is equal to ____.
View Solution
If \( \int_0^\pi \frac{5^{\cos x} (1 + \cos x \cos 3x + \cos^2 x + \cos^3 x \cos 3x)}{1 + 5^{\cos x}} dx = \frac{k \pi}{16}, \) then \( k \) is equal to ____.
View Solution
Let the sixth term in the binomial expansion of \[ \left( \sqrt{2^{\log_2(10 - 3^x)}} + 5 \cdot \sqrt{2^{(x-2)\log_2 3}} \right)^m, \]
in the increasing powers of \( 2^{(x-2)\log_2 3} \), be 21. If the binomial coefficients of the second, third, and fourth terms in the expansion are respectively the first, third, and fifth terms of an A.P., then the sum of the squares of all possible values of \( x \) is ____.
View Solution
If the term without \(x\) in the expansion of \[ \left( x^{\frac{2}{3}} + \frac{\alpha}{x^3} \right)^{22} \]
is \(7315\), then \(|\alpha|\) is equal to ____.
View Solution
The sum of the common terms of the following three arithmetic progressions:
- \( 3, 7, 11, 15, \dots, 399 \),
- \( 2, 5, 8, 11, \dots, 359 \),
- \( 2, 7, 12, 17, \dots, 197 \),
is equal to ____.
View Solution
Let \( \alpha x + \beta y + yz = 1 \) be the equation of a plane passing through the point \((3, -2, 5)\) and perpendicular to the line joining the points \((1, 2, 3)\) and \((-2, 3, 5)\). Then the value of \( \alpha \beta y \) is equal to ____.
View Solution
The point of intersection \(C\) of the plane \(8x + y + 2z = 0\) and the line joining the points \(A(-3, -6, 1)\) and \(B(2, 4, -3)\) divides the line segment \(AB\) internally in the ratio \(k:1\). If \(a, b, c\) (\(|a|, |b|, |c|\) are coprime) are the direction ratios of the perpendicular from the point \(C\) on the line \(\frac{1 - x}{1} = \frac{y + 4}{2} = \frac{z + 2}{3}\), then \(|a + b + c|\) is equal to ____.
View Solution
Also Check:
JEE Main 2023 Mathematics Analysis Feb 1 Shift 2
JEE Main 2023 Paper Analysis for Mathematics paper scheduled on February 1 Shift 2 will be updated here after the conclusion of the exam. Candidates will be able to check subject-wise paper analysis for Mathematics paper scheduled on February 1 Shift 2 here along with the topics with the highest weightage.
| JEE Main 2023 Paper Analysis Feb 1 Shift 2 (After Exam) |
JEE Main 2023 Mathematics Question Paper Pattern
| Feature | Question Paper Pattern |
|---|---|
| Examination Mode | Computer-based Test |
| Exam Language | 13 languages (English, Hindi, Assamese, Bengali, Gujarati, Kannada, Malayalam, Marathi, Odia, Punjabi, Tamil, Telugu, and Urdu) |
| Exam Duration | 3 hours |
| Sectional Time Limit | None |
| Mathematics Marks | 100 marks |
| Total Number of Questions Asked | 20 MCQs + 10 Numerical Type Questions |
| Total Number of Questions to be Answered | 20 MCQs + 5 Numerical Type Questions |
| Marking Scheme | +4 for each correct answer |
| Negative Marking | -1 for each incorrect answer |
Also Check:
JEE Main 2022 Question Paper
JEE Main 2023 aspirants can practice and check their exam prep level by attempting the previous year question papers as well. The table below shows JEE Main 2022 Question Paper PDF for B.E./B.Tech to practice.








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